A yellow seeded and violet flowered pea plant was crossed with a green seeded and white flowered pea plant. The progeny showed plants with four different phenotypes. The yellow seeded and violet flowered parent must be:
1. Double homozygous
2. Double heterozygous
3. Homozygous for seed colour and heterozygous for flower colour.
4. Heterozygous for seed colour and homozygous for flower colour.
Subtopic:  Dihybrid Cross Analysis |
 66%
NEET - 2024
Please attempt this question first.
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): Mendel's law of Independent assortment does not hold good for the genes that are located closely on the same chromosome.
Reason (R): Closely located genes assort independently.

 
In the light of the above statements, choose the correct answer from the options given below:

1. (A) is false, (R) is true.
2. Both (A) and (R) are true and (R) correctly explains (A).
3. Both (A) and (R) are false and (R) does not correctly explain (A).
4. (A) is true, (R) is false.
Subtopic:  Dihybrid Cross Analysis | Linkage Types | Recombination & Gene Mapping |
 67%
From NCERT
NEET - 2022
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
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NEET 2025 - Target Batch

What is the expected percentage of F2 progeny with yellow and inflated pod in dihybrid cross experiment involving pea plants with green coloured, inflated pod and yellow coloured constricted pod ?
1. 100%
2. 56.25%
3. 18.75 %
4. 9%
Subtopic:  Dihybrid Cross Analysis |
 53%
From NCERT
NEET - 2022
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch