Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity?
1. 2.
3. 4.

         
Subtopic:  Acceleration |
 70%
Level 2: 60%+
Please attempt this question first.
Hints
Please attempt this question first.

The position of a particle as a function of time \(t\), is given by;
\(x(t)=a t+b t^2-c t^3\)
where \(a\), \(b\) and \(c\) are constants. When the particle attains zero acceleration, then its velocity will be:
1. \( a+\frac{b^2}{4 c} \)
2. \( a+\frac{b^2}{c} \)
3. \( a+\frac{b^2}{3 c} \)
4. \( a+\frac{b^2}{2 c}\)

Subtopic:  Acceleration |
 84%
Level 1: 80%+
JEE
Please attempt this question first.
Hints
Please attempt this question first.

A particle is moving in a straight line such that its velocity is increasing at \(5\) ms-1 per meter. The acceleration of the particle at a point where its velocity is \(20\) ms-1, is:
1. \(100\) ms-2
2. \(200\) ms-2
3. \(300\) ms-2
4. \(400\) ms-2
Subtopic:  Acceleration |
 74%
Level 2: 60%+
JEE
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

A train (moving with initial speed = \(20\) m/s) applies brakes to stop at the incoming station which is \(500\) m ahead. If brakes are applied after moving \(250\) m, then how much beyond the station train would stop?
1. \(125\) m
2. \(500\) m
3. \(250\) m
4. \(400\) m
Subtopic:  Acceleration |
 72%
Level 2: 60%+
JEE
Please attempt this question first.
Hints
Please attempt this question first.

Given below are two statements:
Statement I: We can get displacement from the acceleration-time graph.
Statement II: We can get acceleration from the velocity-time graph.
 
1. Both Statement I and Statement II are correct.
2. Both Statement I and Statement II are incorrect.
3. Statement I is correct and Statement II is incorrect.
4. Statement I is incorrect and Statement II is correct.
Subtopic:  Acceleration |
 68%
Level 2: 60%+
Please attempt this question first.
Hints
Please attempt this question first.

In a straight-road car race, car \({A}\) reaches the finish line \(t\) seconds earlier than car \({B}\) and has a final speed \(v\) greater than the speed of car \({B}.\) Both cars start from rest and move with constant accelerations \(a_1\) and \(a_2\)​ respectively. Then, \(v\) is equal to:
1. \(\dfrac{2a_1a_1 }{a_1+a_2}~{t}\) 2. \(\sqrt{2a_1a_2}~{t}\)
3. \(\sqrt{a_1a_2}~{t} \) 4. \(\dfrac{a_1+a_2 }{2}~{t}\)
Subtopic:  Acceleration |
Level 3: 35%-60%
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

The distance \(x\) covered by a particle in one-dimensional motion varies with time \(t\) as \(x^2=at^2+2bt+c.\) The acceleration of the particle depends on:
1. \(x^{-3} \)
2. \(x^{-5} \)
3. \(x^{-6} \)
4. \(x^{-1} \)
Subtopic:  Acceleration |
Please attempt this question first.
Hints
Please attempt this question first.

A car accelerates from rest at a constant rate \(\alpha\) for some time, after which it decelerates at a constant rate \(\beta\) to come to rest. If the total time elapsed is \(t~\text{seconds},\)  then the total distance traveled is:
1. \(\dfrac{4 \alpha \beta}{(\alpha+\beta)} t^2\)
2. \(\dfrac{\alpha \beta}{4(\alpha+\beta)} t^2\)
3. \(\dfrac{2 \alpha \beta}{(\alpha+\beta)} t^2\)
4. \(\dfrac{\alpha \beta}{2(\alpha+\beta)} t^2\)
Subtopic:  Acceleration |
Please attempt this question first.
Hints
Please attempt this question first.

The relation between time \({t}\) and distance \({x}\) for a moving body is given as \({t=mx^2+nx},\) where \(m\) and \(n\) are constants. The retardation of the motion is:
(Where \(v\) stands for velocity)
1. \({2n^2v^2}\)
2. \({2mnv^3}\)
3. \({2mv^3}\)
4. \({2nv^3}\)
Subtopic:  Acceleration |
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

If the velocity of a body related to displacement \({x}\) is given by \(v=\sqrt{5000+24 x}~\text{m/s},\) then the acceleration of the body is:
1. \(3~\text{m/s}^2\)
2. \(6~\text{m/s}^2\)
3. \(9~\text{m/s}^2\)
4. \(12~\text{m/s}^2\)
Subtopic:  Acceleration |
Please attempt this question first.
Hints
Please attempt this question first.