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Q. No.
The expression for the longest wavelength in the Paschen series (for \(\mathrm{H}\) atom) is \(\dfrac{144}{xR}.\) Then the value of \({x}\) is:
(\(R\) is Rydberg’s constant).
1. \(5\)
2. \(6\)
3. \(7\)
4. \(8\)
Subtopic:  Spectral Series |
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Level 1: 80%+
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Match List-I (Spectral Series) with List-II (corresponding wave number expressions).
List-I
(Series)		 List-II
(Wave number in \(\text{cm}^{–1}\))
A. Balmer series I. \( R\left(\dfrac{1}{1^2}-\dfrac{1}{n^2}\right) \)
B. Lyman series II. \( R\left(\dfrac{1}{4^2}-\dfrac{1}{n^2}\right) \)
C. Brackett series III. \( R\left(\dfrac{1}{5^2}-\dfrac{1}{n^2}\right) \)
D. Pfund series  IV. \( R\left(\dfrac{1}{2^2}-\dfrac{1}{n^2}\right)\)


Choose the correct answer from the options given below:
 
1. A-I, B-IV, C-III, D-II
2. A-II, B-III, C-IV, D-I
3. A-IV, B-I, C-II, D-III
4. A-III, B-II, C-I, D-IV
Subtopic:  Spectral Series |
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The diagram shown represents different transitions of electron \(({A,B,C,D})\) between the energy levels with the energies mentioned. Among the shown transitions, which transition will generate a photon of wavelength \(124.1~\text{nm}?\)
(\(hc=1241~\text{eV-nm}\)).
          
1. \({A}\)
2. \({B}\)
3. \({C}\)
4. \({D}\)
Subtopic:  Spectral Series |
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Hydrogen \(({ }_1 \mathrm{H}^1)\), Deuterium \(({ }_1 \mathrm{H}^2)\), singly ionised Helium \(({ }_2 \mathrm{He}^4)^+\) and doubly ionised lithium \(({ }_3 \mathrm{Li}^6)^{++}\) all have one electron around the nucleus. Consider an electron transition from \(n=2 \) to \(n=1 \). If the wavelengths of emitted radiation are \(\lambda_1,\lambda_2,\lambda_3\) and \(\lambda_4\) respectively then approximately which one of the following is correct?
1. \( \lambda_1=2 \lambda_2=2 \lambda_3=\lambda_4 \)
2. \( \lambda_1=\lambda_2=4 \lambda_3=9 \lambda_4 \)
3. \( \lambda_1=2 \lambda_2=3 \lambda_3=4 \lambda_4 \)
4. \( 4 \lambda_1=2 \lambda_2=2 \lambda_3=\lambda_4\)

Subtopic:  Spectral Series |
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If \({\mathit{\lambda}}_{1}\) and \({\mathit{\lambda}}_{2}\) are the wavelengths of the first members of the Lyman and Paschen series respectively, then \({\mathit{\lambda}}_{1}:{\mathit{\lambda}}_{2}\) is:
1. \(1:3\)
2. \(1:30\)
3. \(7:50\)
4. \(7:108\)
Subtopic:  Spectral Series |
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The transition from the state n = 3 to n = 1 in a hydrogen-like atom results in ultraviolet radiation. How will the Infrared radiation be obtained in the transition?

1. 4 → 2 

2. 4 →3

3. 2 → 1 

4. 3 → 2

Subtopic:  Spectral Series |
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In a sample of hydrogen atoms, one atom goes through a transition \(n=3\rightarrow\) ground state with emitted wavelength \(\lambda_1\). Another atom goes through a transition \(n=2\rightarrow\) ground state with emitted wavelength \(\lambda_2\). The ratio of \(\dfrac{\lambda_1}{\lambda_2}=\)
1. \(\dfrac{6}{5}\) 2. \(\dfrac{5}{6}\)
3. \(\dfrac{27}{32}\) 4. \(\dfrac{32}{27}\)
Subtopic:  Spectral Series |
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The spectral series which corresponds to the electronic transition from the levels \({n}_{2}=5,6,\ldots \) to the level \({n}_{1}=4\mathrm~\) is:
1. Pfund series 2. Brackett series
3. Lyman series 4. Balmer series
Subtopic:  Spectral Series |
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NEET - 2024
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What is the ratio of the maximum wavelength of the Lyman series in the hydrogen spectrum to the maximum wavelength of the Balmer series?

1.  27 : 5

2.  5 : 27

3.  5 : 7

4.  15 : 17

Subtopic:  Spectral Series |
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The longest wavelength associated with Paschen series is : (Given \(R_H=1.097 \times 10^7\) SI unit)
1. \(2.973 \times 10^{-6} \mathrm{~m}\)
2. \(3.646 \times 10^{-6} \mathrm{~m}\)
3. \(1.094 \times 10^{-6} \mathrm{~m}\)
4. \(1.876 \times 10^{-6} \mathrm{~m}\)
 
Subtopic:  Spectral Series |
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Level 2: 60%+
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