In the figure shown here, what is the equivalent focal length of the combination of lenses?
(Assume that all layers are thin)
1. \(-50~\text{cm}\) 2. \(40~\text{cm}\)
3. \(-40~\text{cm}\) 4. \(-100~\text{cm}\)
Subtopic:  Lens Makers' Formula |
 52%
Level 3: 35%-60%
NEET - 2023
Hints

Two similar thin equi-convex lenses, of focal length \(f\) each, are kept coaxially in contact with each other such that the focal length of the combination is \(F_1\). When the space between the two lenses is filled with glycerin which has the same refractive index as that of glass \((\mu = 1.5),\) then the equivalent focal length is \(F_2\). The ratio \(F_1:F_2\) will be:
1. \(3:4\)
2. \(2:1\)
3. \(1:2\)
4. \(2:3\)

Subtopic:  Lens Makers' Formula |
 59%
Level 3: 35%-60%
NEET - 2019
Hints
Links

A double convex lens has a focal length of \(25\) cm. The radius of curvature of one of the surfaces is double of the other. What would be the radii if the refractive index of the material of the lens is \(1.5?\)
1. \(100\) cm, \(50\) cm
2. \(25\) cm, \(50\) cm
3. \(18.75\) cm, \(37.5\) cm
4. \(50\) cm, \(100\) cm

Subtopic:  Lens Makers' Formula |
 78%
Level 2: 60%+
NEET - 2019
Hints
Links

advertisementadvertisement

Two identical thin plano-convex glass lenses (refractive index = \(1.5\)) each having radius of curvature of \(20\) cm are placed with their convex surfaces in contact at the centre. The intervening space is filled with oil of a refractive index of \(1.7\). The focal length of the combination is:
1. \(-20\) cm
2. \(-25\) cm
3. \(-50\) cm
4. \(50\) cm

Subtopic:  Lens Makers' Formula |
 63%
Level 2: 60%+
NEET - 2015
Hints
Links

A plano-convex lens fits exactly into a plano-concave lens. Their plane surfaces are parallel to each other. If lenses are made of different materials of refractive indices \(\mu_1\) and \(\mu_2\) and \(R\) is the radius of curvature of the curved surface of the lenses, then the focal length of the combination is:
1. \(\dfrac{R}{2(\mu_1-\mu_2)}\) 2. \(\dfrac{R}{(\mu_1-\mu_2)}\)
3. \(\dfrac{2R}{(\mu_2-\mu_1)}\) 4. \(\dfrac{R}{2(\mu_1+\mu_2)}\)
Subtopic:  Lens Makers' Formula |
 69%
Level 2: 60%+
AIPMT - 2013
Hints
Links

When a biconvex lens of glass having a refractive index of \(1.47\) is dipped in a liquid, it acts as a plane sheet of glass. The liquid must have a refractive index:

1. equal to that of glass.
2. less than one.
3. greater than that of glass.
4. less than that of glass.
Subtopic:  Lens Makers' Formula |
 81%
Level 1: 80%+
AIPMT - 2012
Hints
Links

advertisementadvertisement

A biconvex lens \((\mu=1.5)\)  has a radius of curvature of magnitude \(20~\text{cm}\). Which one of the following options, best describes, the image formed by an object of height \(2\) cm placed \(30~\text{cm}\) from the lens?
1. virtual, upright, height \(=0.5\) cm
2. real, inverted, height \(=4\) cm
3. real, inverted, height \(=1\) cm
4. virtual, upright, height \(=1\) cm
Subtopic:  Lenses | Lens Makers' Formula | Refraction at Curved Surface |
 71%
Level 2: 60%+
AIPMT - 2011
Hints
Links

A convex lens is dipped in a liquid whose refractive index is equal to the refractive index of the lens. Then its focal length will:
1. become zero.
2. become infinite.
3. become small, but non-zero.
4. remain unchanged.
Subtopic:  Lens Makers' Formula |
 73%
Level 2: 60%+
AIPMT - 2003
Hints
Links

A plane convex lens \((\mu= 1.5)\) has a radius of curvature \(10~\text{cm}\). It is silvered on its plane surface. The focal length of the lens after silvering is:

1. \(10\) cm 2. \(20\) cm
3. \(15\) cm 4. \(25\) cm
Subtopic:  Lens Makers' Formula |
 60%
Level 2: 60%+
AIPMT - 2000
Hints
Links

advertisementadvertisement