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Q. No.Two identical rectangular plane sheet \(A\) and \(B\) each of surface charge density \(\varepsilon_0 \text{Cm}^{-2}\) are placed parallel to each other as shown in figure. The electric field at the mid point \(P\) will be:
1. \(2 ~\text{NC}^{-1}\)
2. \(1~\text{NC}^{-1}\)
3. \(0.5~\text{NC}^{-1}\)
4. zero
1. \(2 ~\text{NC}^{-1}\)
2. \(1~\text{NC}^{-1}\)
3. \(0.5~\text{NC}^{-1}\)
4. zero
Subtopic: Â Electric Field |
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From NCERT
NEET - 2024
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Match List-I with List-II:
(Here symbols have their usual meaning and \(R\) is the radius of the thin shell)
Choose the correct answer from the options given below:
1. A-IV,B-III, C-I,D-II
2. A-I, B-II, C-III, D-IV
3. A-IV,B-III, C-II, D-I
4. A-I, B-III, C-II, D-IV
| List-I (Application of Gauss Law) |
List-II (Value of \(|E|\)) |
||
| A | Field inside thin shell | I | \( \frac{\lambda}{2 \pi \varepsilon_0 r} \hat{n} \) |
| B | Field outside thin shell | II | \( \frac{q}{4 \pi \varepsilon_0 R^2} \hat{r} \) |
| C | Field of thin shell at the surface | III | \( \frac{q}{4 \pi \varepsilon_0 r^2} \hat{r}\) |
| D | Field due to long charged wire | IV | zero |
Choose the correct answer from the options given below:
1. A-IV,B-III, C-I,D-II
2. A-I, B-II, C-III, D-IV
3. A-IV,B-III, C-II, D-I
4. A-I, B-III, C-II, D-IV
Subtopic: Â Gauss's Law |
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From NCERT
NEET - 2024
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A particle of mass \(m\) and charge \(q\) is placed in a uniform electric field \(E\) at \(t=0~\text s.\) The kinetic energy of the particle after time \(t\) is:
1. \(\large\frac{Eqm}{t}\)
2. \(\large\frac{E^2q^2t^2}{2m}\)
3. \(\large\frac{2E^2t^2}{qm}\)
4. \(\large\frac{Eq^2m}{2t^2}\)
1. \(\large\frac{Eqm}{t}\)
2. \(\large\frac{E^2q^2t^2}{2m}\)
3. \(\large\frac{2E^2t^2}{qm}\)
4. \(\large\frac{Eq^2m}{2t^2}\)
Subtopic: Â Electric Field |
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From NCERT
NEET - 2024
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If \(\oint_s \vec{E} \cdot \overrightarrow{d S}=0\) over a surface, then:
| 1. | the electric field inside the surface is necessarily uniform. |
| 2. | the number of flux lines entering the surface must be equal to the number of flux lines leaving it. |
| 3. | the magnitude of electric field on the surface is constant. |
| 4. | all the charges must necessarily be inside the surface. |
Subtopic: Â Gauss's Law |
 78%
From NCERT
NEET - 2023
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An electric dipole is placed at an angle of \(30^\circ\) with an electric field of intensity \(2\times 10^5 ~\text{NC}^{-1}\). It experiences a torque equal to \(4~\text{N-m}\). Calculate the magnitude of charge on the dipole if the dipole length is \(2~\text{cm}\).
| 1. | \(2~\text{mC}\) | 2. | \(8~\text{mC}\) |
| 3. | \(6~\text{mC}\) | 4. | \(4~\text{mC}\) |
Subtopic: Â Electric Dipole |
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From NCERT
NEET - 2023
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According to Gauss law of electrostatics, electric flux through a closed surface depends on:
| 1. | the area of the surface |
| 2. | the quantity of charges enclosed by the surface |
| 3. | the shape of the surface |
| 4. | the volume enclosed by the surface |
Subtopic: Â Gauss's Law |
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NEET - 2023
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A charge \(Q~\mu\text{C}\) is placed at the centre of a cube. The flux coming out from any one of its faces will be: (in SI unit)
| 1. | \(\frac{Q}{\varepsilon_0}\times10^{-6}\) | 2. | \(\frac{2Q}{3\varepsilon_0}\times10^{-3}\) |
| 3. | \(\frac{Q}{6\varepsilon_0}\times10^{-3}\) | 4. | \(\frac{Q}{6\varepsilon_0}\times10^{-6} \) |
Subtopic: Â Gauss's Law |
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From NCERT
NEET - 2023
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Two point charges \({-q}\) and \({+q}\) are placed at a distance of \({L},\) as shown in the figure.
The magnitude of electric field intensity at a distance \({R}~({R}>>{L})\) varies as:
The magnitude of electric field intensity at a distance \({R}~({R}>>{L})\) varies as:
| 1. | \(\frac{1}{{R}^{6}}\) | 2. | \(\frac{1}{{R}^{2}}\) |
| 3. | \(\frac{1}{{R}^{3}}\) | 4. | \(\frac{1}{{R}^{4}}\) |
Subtopic: Â Electric Dipole |
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From NCERT
NEET - 2022
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Twelve point charges each of charge \(q\) C are placed at the circumference of a circle of radius \(r\) m with equal angular spacing. If one of the charges is removed, the net electric field (in N/C) at the centre of the circle is:
(\(\varepsilon_0 \)-permittivity of free space)
1. \(\frac{13q}{4\pi \varepsilon_0r^2}\)
2. zero
3. \(\frac{q}{4\pi \varepsilon_0r^2}\)
4. \(\frac{12q}{4\pi \varepsilon_0r^2}\)
Subtopic: Â Electric Field |
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From NCERT
NEET - 2022
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The ratio of coulomb's electrostatic force to the gravitational force between an electron and a proton separated by some distance is \(2.4\times 10^{39}\). The ratio of the proportionality constant, \(K=\frac{1}{4\pi\varepsilon_0}\) to the gravitational constant \(G\) is nearly:
(Given that the charge of the proton and electron each \(=1.6\times 10^{-19}\), the mass of the electron = \(9.11\times 10^{-31}\) kg, the mass of the proton \(=1.67\times 10^{-27}\) kg):
(Given that the charge of the proton and electron each \(=1.6\times 10^{-19}\), the mass of the electron = \(9.11\times 10^{-31}\) kg, the mass of the proton \(=1.67\times 10^{-27}\) kg):
| 1. | \(10^{20}\) | 2. | \(10^{30}\) |
| 3. | \(10^{40}\) | 4. | \(10\) |
Subtopic: Â Coulomb's Law |
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NEET - 2022
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