Let \(\omega_{1},\omega_{2}\) and \(\omega_{3}\) be the angular speed of the second hand, minute hand, and hour hand of a smoothly running analog clock, respectively. If \(x_{1},x_{2}\) and \(x_{3}\) are their respective angular distance in \(1\) minute then the factor which remains constant \((k)\) is:
1. \(\dfrac{\omega_1}{x_1}=\dfrac{\omega_2}{x_2}=\dfrac{\omega_3}{x_3}={k}\)
2. \(\omega_{1}x_{1}=\omega_{2}x_{2}=\omega_{3}x_{3}={k}\)
3. \(\omega_{1}x_{1}^{2}=\omega_{2}x_{2}^{2}=\omega_{3}x_{3}^{2}={k}\)
4. \(\omega_{1}^{2}x_{1}=\omega_{2}^{2}x_{2}=\omega_{3}^{2}x_{3}={k}\)