Given below are two statements:
| Assertion (A): | A solution containing a mixture of acetic acid and sodium acetate maintains a constant value of pH on the addition of small amounts of acid or alkali. |
| Reason (R): | A solution containing a mixture of acetic acid and sodium acetate acts as a buffer solution. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
The ratio of the concentration of salt and acid for preparing a buffer solution of pH 6 by mixing sodium acetate and acetic acid will be: (Ka=10-5)
1. 1:10
2. 10:1
3. 100:1
4. 1:100
The pKa of HCN is 9.30. The pH of a solution prepared by mixing 2.5 moles of KCN and 2.5 moles of HCN in water and making up the total volume to 500 ml will be:
| 1. | 9.30 | 2. | 8.30 |
| 3. | 7.30 | 4. | 10.30 |
The basic buffer solution among the following is:
1.
2.
3.
4.
At 25°C, the pH of a solution containing 0.10 M sodium acetate and 0.03 M acetic acid will be:
[pKa value of ]
1. 3.24
2. 4.59
3. 5.09
4. 6.67
Find the ratio [Salt]/[Acid] in an acidic buffer having pH = 5.7 and pKₐ = 5.0.
1. Three (3)
2. Four (4)
3. Five (5)
4. Six (6)
Find the pair of solutions that can be mixed to prepare an acidic buffer.
1. Sodium chloride and sodium hydroxide
2. Sulphuric acid and sodium sulphate
3. Ammonium chloride and ammonium nitrate
4. Ammonium acetate and acetic acid
Find the pH of a buffer prepared by mixing 10 mL of 1.0 M CH₃COOH with 20 mL of 0.5 M CH₃COONa and diluting the mixture to 100 mL with distilled water. Given:
pKₐ(CH₃COOH) = 4.76
1. 5.21
2. 4.76
3. 4.34
4. 5.35
Which of the following combinations can be used to prepare a buffer solution?
I. Sodium acetate and acetic acid in water
II. Sodium acetate and hydrochloric acid in water
III. Ammonia and ammonium chloride in water
IV. Ammonia and sodium hydroxide in water.
1. I, III, IV
2. III, IV
3. I, II, IV
4. I, III
The concentration of ion in a solution containing 0.1 M HCN and 0.2 M NaCN will be:
( for HCN = )
1. 3.1
2.
3.
4.