The motion of a particle along a straight line is described by the equation $$x = 8+12t-t^3$$ where $$x$$ is in meter and $$t$$ in seconds. The retardation of the particle, when its velocity becomes zero, is:
1. $$24$$ ms-2
2. zero
3. $$6$$ ms-2
4. $$12$$ ms-2

Subtopic: Â Acceleration |
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From NCERT
AIPMT - 2012
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A particle moves a distance $$x$$ in time $$t$$ according to equation $$x=(t+5)^{-1}.$$ The acceleration of the particle is proportional to:
1. (velocity)$$3/2$$
2. (distance)$$2$$
3. (distance)$$-2$$
4. (velocity)$$2/3$$

Subtopic: Â Acceleration |
Â 70%
From NCERT
AIPMT - 2010
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A particle starts its motion from rest under the action of a constant force. If the distance covered in the first $$10$$ s is $$S_1$$ and that covered in the first $$20$$ s is $$S_2$$, then:
1. $$S_2=2S_1$$
2. $$S_2 = 3S_1$$
3. $$S_2 = 4S_1$$
4. $$S_2= S_1$$

Subtopic: Â Acceleration |
Â 70%
From NCERT
AIPMT - 2009
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The motion of a particle is given by the equation $S=\left(3{t}^{3}+7{t}^{2}+14t+8\right)m,$ The value of the acceleration of the particle at t = 1 s is :

 1 10 m/s2 2 32 m/s2 3 23 m/s2 4 16 m/s2
Subtopic: Â Acceleration |
Â 93%
From NCERT
AIPMT - 2000
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