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A car is moving along a straight line, say OP in the figure. It moves from O to P in \(18\) s and returns from P to Q in \(6.0\) s. The average velocity and average speed of the car in going from O to P and back to Q respectively are:

1. \(10\) m/s & \(10\) m/s

2. \(20\) m/s & \(30\) m/s

3. \(20\) m/s & \(20\) m/s

4. \(10\) m/s & \(20\) m/s

Subtopic: Average Speed & Average Velocity |

71%

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The position of an object moving along \(x\)-axis is given by \(x=a+bt^2\), where \(a=8.5\) m, \(b=2.5 \text{ ms}^{-2}\) and \(t\) is measured in seconds. Its average velocity between \(t=2.0\) s and \(t=4.0\) s is:

1. | \(10\) m/s | 2. | \(15\) m/s |

3. | \(20\) m/s | 4. | \(25\) m/s |

Subtopic: Average Speed & Average Velocity |

64%

From NCERT

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Which of the following does not represent the equation of motion for constant acceleration?

1. | \(v=v_0+at\) | 2. | \(v^2=v_0^2+2a(x-x_0)\) |

3. | \(x = x_0v_0+\dfrac{1}{2}at^2\) | 4. | \(x = x_0+v_0t+\dfrac{1}{2}at^2\) |

Subtopic: Uniformly Accelerated Motion |

70%

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A ball is thrown vertically upwards with a velocity of \(20\) m/s from the top of a multistorey building. The height of the point from where the ball is thrown is \(25.0\) m from the ground. How high will the ball rise from the point of throw?

(Take \(g=10\) m/s^{2})

(Take \(g=10\) m/s

1. | \(30\) m | 2. | \(25\) m |

3. | \(45\) m | 4. | \(20\) m |

Subtopic: Uniformly Accelerated Motion |

71%

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A ball is thrown vertically upwards with a velocity of \(20\) m/s from the top of a multistorey building. The height of the point from where the ball is thrown is \(25.0\) m from the ground. How long will it be before the ball hits the ground?

(Take \(g=10\) ms^{–2}.)

1. \(3\) s

2. \(2\) s

3. \(5\) s

4. \(20\) s

Subtopic: Uniformly Accelerated Motion |

70%

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When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity \({v_0}\) and the braking capacity, or deceleration, \(-a\) that is caused by the braking. Expression for stopping distance of a vehicle in terms of \({v_0}\) and \(a\) is:

1. | \(\dfrac{{v_o}^2}{2a}\) | 2. | \(\dfrac{{v_o}}{2a}\) |

3. | \(\dfrac{{v_o}^2}{a}\) | 4. | \(\dfrac{2a}{{v_o}^2}\) |

Subtopic: Acceleration |

84%

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You can measure your reaction time by a simple experiment. Take a ruler and ask your friend to drop it vertically through the gap between your thumb and forefinger (figure shown below). After you catch it if the distance d travelled by the ruler is \(21.0\) cm, your reaction time is:

1. | \(0.2\) s | 2. | \(0.4\) s |

3. | \(0\) | 4. | \(0.1\) s |

Subtopic: Uniformly Accelerated Motion |

62%

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Galileo’s law of odd numbers: The distances traversed, during equal intervals of time, by a body falling from rest, stand to one another in the ratio:

1. | as the odd numbers beginning with unity. |

2. | as the even numbers beginning with unity. |

3. | as the square of odd numbers beginning with unity. |

4. | as the square of even numbers beginning with unity. |

Subtopic: Uniformly Accelerated Motion |

81%

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A train is moving in south with a speed of 90 ${\mathrm{kmh}}^{-1}$. The velocity of ground with respect to the train is:

1. 0 ${\mathrm{ms}}^{-1}$

2. -25 ${\mathrm{ms}}^{-1}$

3. 25 ${\mathrm{ms}}^{-1}$

4. -40 ${\mathrm{ms}}^{-1}$

Subtopic: Relative Motion in One Dimension |

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Two parallel rail tracks run north-south. Train A moves north with a speed of 54 ${\mathrm{kmh}}^{-1}$, and train B moves south with a speed of 90 ${\mathrm{kmh}}^{-1}$. The magnitude of the velocity of B with respect to A is:

1. 40 ${\mathrm{ms}}^{-1}$

2. 0 ${\mathrm{ms}}^{-1}$

3. 25 ${\mathrm{ms}}^{-1}$

4. 15 ${\mathrm{ms}}^{-1}$

Subtopic: Relative Motion in One Dimension |

80%

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