The net resistance of the circuit between \(A\) and \(B\) is:
1. | \(\frac{8}{3}~\Omega\) | 2. | \(\frac{14}{3}~\Omega\) |
3. | \(\frac{16}{3}~\Omega\) | 4. | \(\frac{22}{3}~\Omega\) |
What is the equivalent resistance between points a and b, if the value of each resistance is R?
1. | 7R | 2. | 5R |
3. | 4R | 4. | 3R |
In the circuit shown in the figure below, the current supplied by the battery is:
1. 2 A
2. 1 A
3. 0.5 A
4. 0.4 A
In a Wheatstone bridge, all four arms have equal resistance \(R.\) If the resistance of the galvanometer arm is also \(R,\) the equivalent resistance of the combination is:
1. | \(R/4\) | 2. | \(R/2\) |
3. | \(R\) | 4. | \(2R\) |
In the circuit shown in the figure below, if the potential difference between B and D is zero, then value of the unknown resistance X is:
1. | 4 Ω | 2. | 2 Ω |
3. | 3 Ω | 4. | EMF of a cell is required to find the value of X |
Three resistances \(\mathrm P\), \(\mathrm Q\), and \(\mathrm R\), each of \(2~\Omega\) and an unknown resistance \(\mathrm{S}\) form the four arms of a Wheatstone bridge circuit. When the resistance of \(6~\Omega\) is connected in parallel to \(\mathrm{S}\), the bridge gets balanced. What is the value of \(\mathrm{S}\)?
1. \(2~\Omega\)
2. \(3~\Omega\)
3. \(6~\Omega\)
4. \(1~\Omega\)
Figure (a) below shows a Wheatstone bridge in which P, Q R, S are fixed resistances, \(G\) is a galvanometer, and \(B\) is a battery. For this particular case, the galvanometer shows zero deflection. Now, only the positions of \(B\) and \(G\) are interchanged. as shown in figure (b). The new deflection of the galvanometer:
1. | is to the left |
2. | is to the right |
3. | is zero |
4. | depends on the values of P, Q, R, S |
Column I | Column II | ||
(A) | Equivalent resistance between \(a\) and \(b\) | (P) | \(\dfrac{R}{2}\) |
(B) | Equivalent resistance between \(a\) and \(c\) | (Q) | \(\dfrac{5R}{8}\) |
(C) | Equivalent resistance between \(b\) and \(d\) | (R) | \(R\) |
1. | A → P, B → Q, C → R |
2. | A → Q, B → P, C → R |
3. | A → R, B → P, C → Q |
4. | A → R, B → Q, C → P |
For the network shown in the figure below, the value of the current i is:
1.
2.
3.
4.