Two solid conductors are made up of the same material and have the same length and the same resistance. One of them has a circular cross-section of area and the other one has a square cross-section of area . The ratio is:
1. | \(1.5\) | 2. | \(1\) |
3. | \(0.8\) | 4. | \(2\) |
For the circuit given below, Kirchhoff's loop rule for the loop \(BCDEB\) is given by the equation:
1. | \(-{i}_2 {R}_2+{E}_2-{E}_3+{i}_3{R}_1=0\) |
2. | \({i}_2{R}_2+{E}_2-{E}_3-{i}_3 {R}_1=0\) |
3. | \({i}_2 {R}_2+{E}_2+{E}_3+{i}_3 {R}_1=0\) |
4. | \(-{i}_2 {R}_2+{E}_2+{E}_3+{i}_3{R}_1=0\) |
The equivalent resistance between \(A\) and \(B\) for the mesh shown in the figure is:
1. | \(7.2\) \(\Omega\) | 2. | \(16\) \(\Omega\) |
3. | \(30\) \(\Omega\) | 4. | \(4.8\) \(\Omega\) |
A cell having an emf \(\varepsilon\) and internal resistance \(r\) is connected across a variable external resistance \(R\). As the resistance \(R\) is increased, the plot of potential difference \(V\) across \(R\) is given by:
1. | 2. | ||
3. | 4. |
In the circuit shown in the figure below, if the potential at point \(A\) is taken to be zero, the potential at point \(B\) will be:
1. \(+1\) V
2. \(-1\) V
3. \(+2\) V
4. \(-2\) V
For the circuit shown in the figure, the current \(I\) will be:
1. | \(0.75~\text{A}\) | 2. | \(1~\text{A}\) |
3. | \(1.5~\text{A}\) | 4. | \(0.5~\text{A}\) |
The net resistance of the circuit between \(A\) and \(B\) is:
1. | \(\frac{8}{3}~\Omega\) | 2. | \(\frac{14}{3}~\Omega\) |
3. | \(\frac{16}{3}~\Omega\) | 4. | \(\frac{22}{3}~\Omega\) |
Two batteries, one of emf \(18\) volts and internal resistance \(2~\Omega\) and the other of emf \(12\) V and internal resistance \(1~\Omega,\) are connected as shown. The voltmeter \(\mathrm{V}\) will record a reading of:
1. \(18\) V
2. \(30\) V
3. \(14\) V
4. \(15\) V
A \(5\text-\)ampere fuse wire can withstand a maximum power of \(1\) watt in a circuit. The resistance of the fuse wire is:
1. | \(5~\Omega\) | 2. | \(0.04~\Omega\) |
3. | \(0.2~\Omega\) | 4. | \(0.4~\Omega\) |
For the network shown in the figure below, the value of the current \(i\) is:
1. \(\frac{18V}{5}\)
2. \(\frac{5V}{9}\)
3. \(\frac{9V}{35}\)
4. \(\frac{5V}{18}\)