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In Young’s double slit experiment, the slits are \(2~\text{mm}\) apart and are illuminated by photons of two wavelengths \(\lambda_1 = 12000~\mathring{A}\) and \(\lambda_2 = 10000~\mathring{A}\). At what minimum distance from the common central bright fringe on the screen, \(2~\text{m}\) from the slit, will a bright fringe from one interference pattern coincide with a bright fringe from the other?

1. \(6~\text{mm}\)

2. \(4~\text{mm}\)

3. \(3~\text{mm}\)

4. \(8~\text{mm}\)

Subtopic: Young's Double Slit Experiment |

67%

From NCERT

AIPMT - 2013

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A parallel beam of fast-moving electrons is incident normally on a narrow slit. A fluorescent screen is placed at a large distance from the slit. If the speed of the electrons is increased, which of the following statements is correct?

1. | The angular width of the central maximum of the diffraction pattern will increase. |

2. | The angular width of the central maximum will decrease. |

3. | The angular width of the central maximum will be unaffected. |

4. | A diffraction pattern is not observed on the screen in the case of electrons. |

Subtopic: Diffraction |

51%

From NCERT

AIPMT - 2013

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Two periodic waves of intensities I_{1} and I_{2} pass through a region at the same time in the same direction. The sum of the maximum and minimum intensities is:

1. $2\left({\mathrm{l}}_{1}+{\mathrm{l}}_{2}\right)$

2. ${\left({\sqrt{\mathrm{I}}}_{1}+{\sqrt{\mathrm{l}}}_{2}\right)}^{2}$

3. ${\left({\sqrt{\mathrm{I}}}_{1}-{\sqrt{\mathrm{l}}}_{2}\right)}^{2}$

4. $2\left({\sqrt{\mathrm{I}}}_{1}-{\sqrt{\mathrm{l}}}_{2}\right)$

Subtopic: Superposition Principle |

74%

From NCERT

AIPMT - 2008

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In Young's double-slit experiment, the intensity of light at a point on the screen where the path difference is \(\lambda\) is \(K\), (\(\lambda\) being the wavelength of light used). The intensity at a point where the path difference is \(\frac{\lambda}{4}\) will be:

1. \(K\)

2. \(\frac{K}{4}\)

3. \(\frac{K}{2}\)

4. zero

Subtopic: Young's Double Slit Experiment |

64%

From NCERT

AIPMT - 2014

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A beam of light of \(\lambda = 600~\text{nm}\) from a distant source falls on a single slit \(1~\text{mm}\) wide and the resulting diffraction pattern is observed on a screen \(2~\text{m}\) away. The distance between the first dark fringes on either side of the central bright fringe is:

1. \(1.2~\text{cm}\)

2. \(1.2~\text{mm}\)

3. \(2.4~\text{cm}\)

4. \(2.4~\text{mm}\)

Subtopic: Diffraction |

63%

From NCERT

AIPMT - 2014

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In a double-slit experiment, the two slits are \(1~\text{mm}\) apart and the screen is placed \(1~\text{m}\) away. Monochromatic light of wavelength \(500~\text{nm}\) is used. What will be the width of each slit for obtaining ten maxima of double-slit within the central maxima of a single-slit pattern?

1. \(0.2~\text{mm}\)

2. \(0.1~\text{mm}\)

3. \(0.5~\text{mm}\)

4. \(0.02~\text{mm}\)

2. \(0.1~\text{mm}\)

3. \(0.5~\text{mm}\)

4. \(0.02~\text{mm}\)

Subtopic: Young's Double Slit Experiment |

52%

From NCERT

NEET - 2015

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For a parallel beam of monochromatic light of wavelength \(\lambda\), diffraction is produced by a single slit whose width \(a\) is much greater than the wavelength of the light. If \(D\) is the distance of the screen from the slit, the width of the central maxima will be:

1. | \(\dfrac{2D\lambda}{a}\) | 2. | \(\dfrac{D\lambda}{a}\) |

3. | \(\dfrac{Da}{\lambda}\) | 4. | \(\dfrac{2Da}{\lambda}\) |

Subtopic: Diffraction |

82%

From NCERT

NEET - 2015

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At the first minimum adjacent to the central maximum of a single slit diffraction pattern, the phase difference between the Huygen’s wavelet from the edge of the slit and the wavelet from the midpoint of the slit is:

1. \(\frac{\pi}{4}\text{radian}\)

2. \(\frac{\pi}{2}\text{radian}\)

3. \({\pi}~\text{radian}\)

4. \(\frac{\pi}{8}\text{radian}\)

Subtopic: Diffraction |

59%

From NCERT

NEET - 2015

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Two slits in Young’s experiment have widths in the ratio of \(1:25\). The ratio of intensity at the maxima and minima in the interference pattern \(\frac{I_{max}}{I_{min}}\) is:

1. | \(\dfrac{9}{4}\) | 2. | \(\dfrac{121}{49}\) |

3. | \(\dfrac{49}{121}\) | 4. | \(\dfrac{4}{9}\) |

Subtopic: Young's Double Slit Experiment |

75%

From NCERT

NEET - 2015

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In Young's-double slit experiment, the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width:

1. | is halved |

2. | become four times |

3. | remains unchanged |

4. | is doubled |

Subtopic: Young's Double Slit Experiment |

79%

From NCERT

NEET - 2013

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