If \(\oint_s \vec{E} \cdot \overrightarrow{d S}=0\) over a surface, then:
 
1. the electric field inside the surface is necessarily uniform.
2. the number of flux lines entering the surface must be equal to the number of flux lines leaving it.
3. the magnitude of electric field on the surface is constant.
4. all the charges must necessarily be inside the surface.
Subtopic:  Gauss's Law |
 77%
From NCERT
NEET - 2023
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An electric dipole is placed at an angle of \(30^\circ\) with an electric field of intensity \(2\times 10^5 ~\mathrm{NC^{-1}}\). It experiences a torque equal to \(4~\mathrm{N \text-m}\). Calculate the magnitude of charge on the dipole, if the dipole length is \(2\) cm.
1. \(2~\mathrm{mC}\) 2. \(8~\mathrm{mC}\)
3. \(6~\mathrm{mC}\) 4. \(4~\mathrm{mC}\)
Subtopic:  Electric Dipole |
 68%
From NCERT
NEET - 2023
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According to Gauss law of electrostatics, electric flux through a closed surface depends on:
1. the area of the surface
2. the quantity of charges enclosed by the surface
3. the shape of the surface
4. the volume enclosed by the surface
Subtopic:  Gauss's Law |
 81%
From NCERT
NEET - 2023
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A charge \(Q~\mu \text{C}\) is placed at the centre of a cube. The flux coming out from any one of its faces will be(in SI unit):
1. \(\frac{Q}{\varepsilon_0}\times10^{-6}\)
2. \(\frac{2Q}{3\varepsilon_0}\times10^{-3}\)
3. \(\frac{Q}{6\varepsilon_0}\times10^{-3}\)
4. \(\frac{Q}{6\varepsilon_0}\times10^{-6}\)
Subtopic:  Gauss's Law |
 73%
From NCERT
NEET - 2023
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Two point charges \({-q}\) and \({+q}\) are placed at a distance of \({L},\) as shown in the figure.
        
The magnitude of electric field intensity at a distance \({R}~({R}>>{L})\) varies as:
1. \(\frac{1}{{R}^{6}}\) 2. \(\frac{1}{{R}^{2}}\)
3. \(\frac{1}{{R}^{3}}\) 4. \(\frac{1}{{R}^{4}}\)
Subtopic:  Electric Dipole |
 69%
From NCERT
NEET - 2022
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Twelve point charges each of charge \(q\) C are placed at the circumference of a circle of radius \(r\) m with equal angular spacing. If one of the charges is removed, the net electric field (in N/C) at the centre of the circle is:
(\(\varepsilon_0 \)-permittivity of free space)
1. \(\frac{13q}{4\pi \varepsilon_0r^2}\)
2. zero
3. \(\frac{q}{4\pi \varepsilon_0r^2}\)
4. \(\frac{12q}{4\pi \varepsilon_0r^2}\)

Subtopic:  Electric Field |
 62%
From NCERT
NEET - 2022
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The ratio of coulomb's electrostatic force to the gravitational force between an electron and a proton separated by some distance is \(2.4\times 10^{39}\). The ratio of the proportionality constant, \(K=\frac{1}{4\pi\varepsilon_0}\) to the gravitational constant \(G\) is nearly:
(Given that the charge of the proton and electron each \(=1.6\times 10^{-19}\), the mass of the electron = \(9.11\times 10^{-31}\) kg, the mass of the proton \(=1.67\times 10^{-27}\) kg):
1. \(10^{20}\) 2. \(10^{30}\)
3. \(10^{40}\) 4. \(10\)
Subtopic:  Coulomb's Law |
 59%
From NCERT
NEET - 2022
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Polar molecules are the molecules:

1. that acquires a dipole moment only when the magnetic field is absent.
2. has a permanent electric dipole moment.
3. has zero dipole moment.
4. that acquire a dipole moment only in the presence of an electric field due to displacement of charges.
Subtopic:  Electric Dipole |
 63%
From NCERT
NEET - 2021
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A dipole is placed in an electric field as shown. In which direction will it move? 

   

1. towards the left as its potential energy will decrease.
2. towards the right as its potential energy will increase.
3. towards the left as its potential energy will increase.
4. towards the right as its potential energy will decrease.
Subtopic:  Electric Dipole |
From NCERT
NEET - 2021
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A spherical conductor of radius \(10~\text{cm}\) has a charge of \(3.2 \times 10^{-7}~\text{C}\) distributed uniformly. What is the magnitude of the electric field at a point \(15~\text{cm}\) from the center of the sphere? \(\frac{1}{4\pi \varepsilon _0} = 9\times 10^9~\text{N-m}^2/\text{C}^2\)
1. \(1.28\times 10^{5}~\text{N/C}\)
2. \(1.28\times 10^{6}~\text{N/C}\)
3. \(1.28\times 10^{7}~\text{N/C}\)
4. \(1.28\times 10^{4}~\text{N/C}\)

Subtopic:  Electric Field |
 64%
From NCERT
NEET - 2020
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