We can charge a metal sphere positively without touching it by:

1. Conduction

2. Induction

3. Friction

4. Both (1) and (2)

67%

Subtopic: Electric Charge |

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

Please attempt this question first.

Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's **Unique MCQ Books** with Online **Audio/Video/Text Solutions via Telegram Bot**

If 10^{9} electrons move out of a body to another body every second, how much time approximately is required to get a total charge of 1 C on the other body?

1. 200 years

2. 100 years

3. 150 years

4. 250 years

55%

Subtopic: Electric Charge |

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

Please attempt this question first.

Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's **Unique MCQ Books** with Online **Audio/Video/Text Solutions via Telegram Bot**

The amount of positive and negative charges in a cup of water (250 g) are respectively:

$1.1.6\times {10}^{9}C,1.4\times {10}^{9}C\phantom{\rule{0ex}{0ex}}2.1.4\times {10}^{9}C,1.6\times {10}^{9}C\phantom{\rule{0ex}{0ex}}3.1.34\times {10}^{7}C,1.34\times {10}^{7}C\phantom{\rule{0ex}{0ex}}4.1.6\times {10}^{8}C,1.6\times {10}^{7}C$

63%

Subtopic: Electric Charge |

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

Please attempt this question first.

Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's **Unique MCQ Books** with Online **Audio/Video/Text Solutions via Telegram Bot**

The ratio of the magnitude of electric force to the magnitude of gravitational force for an electron and a proton will be: $\left({m}_{p}=1.67\times {10}^{-27}kg,{m}_{e}=9.11\times {10}^{-31}kg\right)$

$1.2.4\times {10}^{39}\phantom{\rule{0ex}{0ex}}2.2.6\times {10}^{36}\phantom{\rule{0ex}{0ex}}3.1.4\times {10}^{36}\phantom{\rule{0ex}{0ex}}4.1.6\times {10}^{39}$

56%

Subtopic: Coulomb's Law |

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

Please attempt this question first.

Launched MCQ Practice Books

**Unique MCQ Books** with Online **Audio/Video/Text Solutions via Telegram Bot**

A charged metallic sphere A is suspended by a nylon thread. Another identical charged metallic sphere B held by an insulating handle is brought close to A such that the distance between their centres is 10 cm, as shown in Fig.(a). The resulting repulsion of A is noted. Then spheres A and B are touched by identical uncharged spheres C and D respectively, as shown in Fig.(b). C and D are then removed and B is brought closer to A to a distance of 5.0 cm between their centres, as shown in Fig. (c). What is the expected repulsion on A on the basis of Coulomb’s law?

1. Electrostatic force on A due to B remains unaltered.

2. Electrostatic force on A due to B becomes double.

3. Electrostatic force on A due to B becomes half.

4. Can't say.

69%

Subtopic: Coulomb's Law |

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

Please attempt this question first.

Launched MCQ Practice Books

**Unique MCQ Books** with Online **Audio/Video/Text Solutions via Telegram Bot**

Consider three charges ${\mathrm{q}}_{1},{\mathrm{q}}_{2,}{\mathrm{q}}_{3}$ each equal to q at the vertices of an equilateral triangle of side l. What is the force on a charge Q (with the same sign as q) placed at the centroid of the triangle, as shown in the figure?

$1.\frac{3}{4{\mathrm{\pi \epsilon}}_{0}}\frac{\mathrm{Qq}}{{\mathrm{l}}^{2}}\phantom{\rule{0ex}{0ex}}2.\frac{9}{4{\mathrm{\pi \epsilon}}_{0}}\frac{\mathrm{Qq}}{{\mathrm{l}}^{2}}\phantom{\rule{0ex}{0ex}}3.\mathrm{Zero}\phantom{\rule{0ex}{0ex}}4.\frac{6}{4{\mathrm{\pi \epsilon}}_{0}}\frac{\mathrm{Qq}}{{\mathrm{l}}^{2}}$

84%

Subtopic: Coulomb's Law |

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

Please attempt this question first.

Launched MCQ Practice Books

**Unique MCQ Books** with Online **Audio/Video/Text Solutions via Telegram Bot**

Consider the charges q, q, and –q placed at the vertices of an equilateral triangle, as shown in the figure. Then the sum of the forces on the three charges is:

$1.\frac{{\mathrm{q}}^{2}}{4{\mathrm{\pi \epsilon}}_{0}{\mathrm{l}}^{2}}\phantom{\rule{0ex}{0ex}}2.\mathrm{Zero}\phantom{\rule{0ex}{0ex}}3.\frac{2{\mathrm{q}}^{2}}{4{\mathrm{\pi \epsilon}}_{0}{\mathrm{l}}^{2}}\phantom{\rule{0ex}{0ex}}4.\frac{3{\mathrm{q}}^{2}}{4{\mathrm{\pi \epsilon}}_{0}{\mathrm{l}}^{2}}$

69%

Subtopic: Coulomb's Law |

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

Please attempt this question first.

Launched MCQ Practice Books

**Unique MCQ Books** with Online **Audio/Video/Text Solutions via Telegram Bot**

An electron falls through a distance of 1.5 cm in a uniform electric field of magnitude $2\times {10}^{4}N{C}^{-1}$ [figure (a)]. The direction of the field is reversed keeping its magnitude unchanged and a proton falls through the same distance [figure (b)]. If ${\mathrm{t}}_{\mathrm{e}}\mathrm{and}{\mathrm{t}}_{\mathrm{p}}$ are the time of fall for electron and proton respectively, then:

$1.{\mathrm{t}}_{\mathrm{e}}={\mathrm{t}}_{\mathrm{p}}$

57%

Subtopic: Electric Field |

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

Please attempt this question first.

Launched MCQ Practice Books

**Unique MCQ Books** with Online **Audio/Video/Text Solutions via Telegram Bot**

Two-point charges ${q}_{1}$ and ${q}_{2}$, of magnitude $+{10}^{-8}C$ and $-{10}^{-8}C$, respectively, are placed 0.1 m apart. The electric field at point A (as shown in the figure) is:

$1.3.6\times {10}^{4}{\mathrm{NC}}^{-1}\phantom{\rule{0ex}{0ex}}2.7.2\times {10}^{4}{\mathrm{NC}}^{-1}\phantom{\rule{0ex}{0ex}}3.9\times {10}^{3}{\mathrm{NC}}^{-1}\phantom{\rule{0ex}{0ex}}4.3.2\times {10}^{4}{\mathrm{NC}}^{-1}$

55%

Subtopic: Electric Field |

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

Please attempt this question first.

Launched MCQ Practice Books

**Unique MCQ Books** with Online **Audio/Video/Text Solutions via Telegram Bot**

Two charges ±10 µC are placed 5.0 mm apart. The electric field at a point P on the axis of the dipole 15 cm away from its centre O on the side of the positive charge, as shown in the figure is:

$1.2.7\times {10}^{5}{\mathrm{NC}}^{-1}\phantom{\rule{0ex}{0ex}}2.4.13\times {10}^{6}{\mathrm{NC}}^{-1}\phantom{\rule{0ex}{0ex}}3.3.86\times {10}^{6}{\mathrm{NC}}^{-1}\phantom{\rule{0ex}{0ex}}4.1.33\times {10}^{5}{\mathrm{NC}}^{-1}$

Subtopic: Electric Dipole |

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

Please attempt this question first.

Launched MCQ Practice Books

**Unique MCQ Books** with Online **Audio/Video/Text Solutions via Telegram Bot**