If \(\oint_s \vec{E} \cdot \overrightarrow{d S}=0\) over a surface, then:
 
1. the electric field inside the surface is necessarily uniform.
2. the number of flux lines entering the surface must be equal to the number of flux lines leaving it.
3. the magnitude of electric field on the surface is constant.
4. all the charges must necessarily be inside the surface.
Subtopic:  Gauss's Law |
 79%
From NCERT
NEET - 2023
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According to Gauss law of electrostatics, electric flux through a closed surface depends on:
1. the area of the surface
2. the quantity of charges enclosed by the surface
3. the shape of the surface
4. the volume enclosed by the surface
Subtopic:  Gauss's Law |
 82%
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A charge \(Q~\mu\text{C}\) is placed at the centre of a cube. The flux coming out from any one of its faces will be: (in SI unit)
1. \(\frac{Q}{\varepsilon_0}\times10^{-6}\) 2. \(\frac{2Q}{3\varepsilon_0}\times10^{-3}\)
3. \(\frac{Q}{6\varepsilon_0}\times10^{-3}\) 4. \(\frac{Q}{6\varepsilon_0}\times10^{-6} \)
Subtopic:  Gauss's Law |
 75%
From NCERT
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Two parallel infinite line charges with linear charge densities \(+\lambda\) C/m and \(+\lambda\) C/m are placed at a distance \({R}.\) The electric field mid-way between the two line charges is:
1. \(\frac{\lambda}{2 \pi \varepsilon_0 {R}} \) N/C
2. zero
3. \(\frac{2\lambda}{ \pi \varepsilon_0 {R}} \) N/C
4. \(\frac{\lambda}{ \pi \varepsilon_0 {R}}\) N/C

Subtopic:  Gauss's Law |
 63%
From NCERT
NEET - 2019
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A sphere encloses an electric dipole with charges \(\pm3\times10^{-6}\) C. What is the total electric flux through the sphere?
1. \(-3\times10^{-6}\) N-m2/C
2. zero
3. \(3\times10^{-6}\) N-m2/C
4. \(6\times10^{-6}\) N-m2/C

Subtopic:  Gauss's Law |
 89%
From NCERT
NEET - 2019
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