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If \(\oint_s \vec{E} \cdot \overrightarrow{d S}=0\) over a surface, then:

1. | the electric field inside the surface is necessarily uniform. |

2. | the number of flux lines entering the surface must be equal to the number of flux lines leaving it. |

3. | the magnitude of electric field on the surface is constant. |

4. | all the charges must necessarily be inside the surface. |

Subtopic: Â Gauss's Law |

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From NCERT

NEET - 2023

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An electric dipole is placed at an angle of \(30^\circ\) with an electric field of intensity \(2\times 10^5 ~\text{NC}^{-1}\). It experiences a torque equal to \(4~\text{N-m}\). Calculate the magnitude of charge on the dipole if the dipole length is \(2~\text{cm}\).

1. | \(2~\text{mC}\) | 2. | \(8~\text{mC}\) |

3. | \(6~\text{mC}\) | 4. | \(4~\text{mC}\) |

Subtopic: Â Electric Dipole |

Â 71%

From NCERT

NEET - 2023

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According to Gauss law of electrostatics, electric flux through a closed surface depends on:

1. | the area of the surface |

2. | the quantity of charges enclosed by the surface |

3. | the shape of the surface |

4. | the volume enclosed by the surface |

Subtopic: Â Gauss's Law |

Â 81%

From NCERT

NEET - 2023

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A charge \(Q~\mu\text{C}\) is placed at the centre of a cube. The flux coming out from any one of its faces will be: (in SI unit)

1. | \(\frac{Q}{\varepsilon_0}\times10^{-6}\) | 2. | \(\frac{2Q}{3\varepsilon_0}\times10^{-3}\) |

3. | \(\frac{Q}{6\varepsilon_0}\times10^{-3}\) | 4. | \(\frac{Q}{6\varepsilon_0}\times10^{-6} \) |

Subtopic: Â Gauss's Law |

Â 74%

From NCERT

NEET - 2023

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Two point charges \({-q}\) and \({+q}\) are placed at a distance of \({L},\) as shown in the figure.

The magnitude of electric field intensity at a distance \({R}~({R}>>{L})\) varies as:

The magnitude of electric field intensity at a distance \({R}~({R}>>{L})\) varies as:

1. | \(\frac{1}{{R}^{6}}\) | 2. | \(\frac{1}{{R}^{2}}\) |

3. | \(\frac{1}{{R}^{3}}\) | 4. | \(\frac{1}{{R}^{4}}\) |

Subtopic: Â Electric Dipole |

Â 70%

From NCERT

NEET - 2022

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Twelve point charges each of charge \(q\) C are placed at the circumference of a circle of radius \(r\) m with equal angular spacing. If one of the charges is removed, the net electric field (in N/C) at the centre of the circle is:

(\(\varepsilon_0 \)-permittivity of free space)

1. \(\frac{13q}{4\pi \varepsilon_0r^2}\)

2. zero

3. \(\frac{q}{4\pi \varepsilon_0r^2}\)

4. \(\frac{12q}{4\pi \varepsilon_0r^2}\)

Subtopic: Â Electric Field |

Â 62%

From NCERT

NEET - 2022

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The ratio of coulomb's electrostatic force to the gravitational force between an electron and a proton separated by some distance is \(2.4\times 10^{39}\). The ratio of the proportionality constant, \(K=\frac{1}{4\pi\varepsilon_0}\) to the gravitational constant \(G\) is nearly:

(Given that the charge of the proton and electron each \(=1.6\times 10^{-19}\), the mass of the electron = \(9.11\times 10^{-31}\) kg, the mass of the proton \(=1.67\times 10^{-27}\) kg):

(Given that the charge of the proton and electron each \(=1.6\times 10^{-19}\), the mass of the electron = \(9.11\times 10^{-31}\) kg, the mass of the proton \(=1.67\times 10^{-27}\) kg):

1. | \(10^{20}\) | 2. | \(10^{30}\) |

3. | \(10^{40}\) | 4. | \(10\) |

Subtopic: Â Coulomb's Law |

Â 60%

From NCERT

NEET - 2022

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Polar molecules are the molecules:

1. | that acquires a dipole moment only when the magnetic field is absent. |

2. | has a permanent electric dipole moment. |

3. | has zero dipole moment. |

4. | that acquire a dipole moment only in the presence of an electric field due to displacement of charges. |

Subtopic: Â Electric Dipole |

Â 64%

From NCERT

NEET - 2021

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A dipole is placed in an electric field as shown. In which direction will it move?

1. | towards the left as its potential energy will decrease. |

2. | towards the right as its potential energy will increase. |

3. | towards the left as its potential energy will increase. |

4. | towards the right as its potential energy will decrease. |

Subtopic: Â Electric Dipole |

From NCERT

NEET - 2021

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A spherical conductor of radius \(10~\text{cm}\) has a charge of \(3.2 \times 10^{-7}~\text{C}\) distributed uniformly. What is the magnitude of the electric field at a point \(15~\text{cm}\) from the center of the sphere? \(\frac{1}{4\pi \varepsilon _0} = 9\times 10^9~\text{N-m}^2/\text{C}^2\)

1. \(1.28\times 10^{5}~\text{N/C}\)

2. \(1.28\times 10^{6}~\text{N/C}\)

3. \(1.28\times 10^{7}~\text{N/C}\)

4. \(1.28\times 10^{4}~\text{N/C}\)

Subtopic: Â Electric Field |

Â 64%

From NCERT

NEET - 2020

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