A transverse harmonic wave on a string is described by, $$y(x,t) = 3.0 sin ( 36t + 0.018x + {\pi \over 4})$$ where x and are in cm and in sec. The positive direction of x is from left to right. What is the shortest distance between two successive crests in the wave?

 1 1.3 m 2 3.0 m 3 2.5 m 4 3.5 m
Subtopic: Â Wave Motion |
Â 67%
From NCERT
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NEET 2023 - Target Batch - Aryan Raj Singh
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NEET 2023 - Target Batch - Aryan Raj Singh

For the travelling harmonic wave, $$y(x,t) = 2.0\ cos\ 2\pi (10t - 0.0080x + 0.35 )$$ where $$x$$ and $$y$$ are in $$\text{cm}$$ and $$t$$ is in seconds. The phase difference between the oscillatory motion of two points separated by a distance of $$4~\text{m}$$ will be:
1. $$0.8 \pi\ \text{rad}$$

2. $$\pi\ \text{rad}$$
3. $$6.4\pi\ \text{rad}$$
4.
$$4\pi\ \text{rad}$$

Subtopic: Â Wave Motion |
Â 67%
From NCERT
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
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