- 1(current)
Q. No.A transverse harmonic wave on a string is described by, \(y(x,t) = 3.0 ~\sin \left(36t + 0.018x + {\dfrac {\pi} 4}\right)\) where \(x\) and \(y\) are in cm and \(t\) in sec. The positive direction of \(x\) is from left to right. What is the shortest distance between two successive crests in the wave?
| 1. | \(1.3\) m | 2. | \(3.0\) m |
| 3. | \(2.5\) m | 4. | \(3.5\) m |
Subtopic: Â Wave Motion |
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For the travelling harmonic wave, \(y(x,t) = 2.0\cos 2\pi (10t - 0.0080x + 0.35 )\) where \(x\) and \(y\) are in \(\text{cm}\) and \(t\) is in seconds. The phase difference between the oscillatory motion of two points separated by a distance of \(4~\text{m}\) will be:
1. \(0.8 \pi~\text{rad}\)
2. \(\pi~ \text{rad}\)
3. \(6.4\pi~\text{rad}\)
4. \(4\pi~\text{rad}\)
1. \(0.8 \pi~\text{rad}\)
2. \(\pi~ \text{rad}\)
3. \(6.4\pi~\text{rad}\)
4. \(4\pi~\text{rad}\)
Subtopic: Â Wave Motion |
 68%
From NCERT
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
Hints
Links
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
- 1(current)
Q. No.
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