- 1(current)
Q. No.The planet Mars has two moons, Phobos and Delmos. Phobos has a period of \(7\) hours, \(39\) minutes and an orbital radius of \(9 . 4 \times 10^{3}\) km. The mass of mars is:
| 1. | \(6 . 48 \times 10^{23} \text{ kg}\) | 2. | \(6 . 48 \times 10^{25} \text{ kg}\) |
| 3. | \(6 . 48 \times 10^{20} \text{ kg}\) | 4. | \(6 . 48 \times 10^{21} \text{ kg}\) |
Subtopic: Satellite |
Level 3: 35%-60%
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You are given the following data: \(g = 9.81~\text{m/s}^{2}\), \(R_{E} = 6 . 37 \times 10^{6}~\text m\), the distance to the moon, \(R = 3 . 84 \times 10^{8}~\text m\) and the time period of the moon’s revolution is \(27.3\) days. Mass of the Earth \(M_{E}\) in two different ways is:
1. \(5 . 97 \times 10^{24} ~ \text{kg and }6 . 02 \times 10^{24} \text{ kg}\)
2. \(5 . 97 \times 10^{24} \text{ kg and } 6 . 02 \times 10^{23} \text{ kg}\)
3. \(5 . 97 \times 10^{23} ~ \text{kg and }6 . 02 \times 10^{24} \text{ kg}\)
4. \(5 . 97 \times 10^{23} \text{ kg and } 6 . 02 \times 10^{23} \text{ kg}\)
1. \(5 . 97 \times 10^{24} ~ \text{kg and }6 . 02 \times 10^{24} \text{ kg}\)
2. \(5 . 97 \times 10^{24} \text{ kg and } 6 . 02 \times 10^{23} \text{ kg}\)
3. \(5 . 97 \times 10^{23} ~ \text{kg and }6 . 02 \times 10^{24} \text{ kg}\)
4. \(5 . 97 \times 10^{23} \text{ kg and } 6 . 02 \times 10^{23} \text{ kg}\)
Subtopic: Satellite |
56%
Level 3: 35%-60%
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Constant \(k = 10^{- 13} ~ \text s^{2}~ \text m^{- 3}\) in days and kilometres is?
1. \(10^{- 13} ~ \text d^{2} ~\text{km}^{- 3}\)
2. \(1 . 33 \times 10^{14} \text{ dkm}^{- 3}\)
3. \(10^{- 13} ~ \text d^{2} ~\text {km}\)
4. \(1 . 33 \times 10^{- 14} \text{ d}^{2} \text{ km}^{- 3}\)
1. \(10^{- 13} ~ \text d^{2} ~\text{km}^{- 3}\)
2. \(1 . 33 \times 10^{14} \text{ dkm}^{- 3}\)
3. \(10^{- 13} ~ \text d^{2} ~\text {km}\)
4. \(1 . 33 \times 10^{- 14} \text{ d}^{2} \text{ km}^{- 3}\)
Subtopic: Satellite |
58%
Level 3: 35%-60%
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The moon is at a distance of \(3.84\times10^5~\text{km}\) from the earth. Its time period of revolution in days is:
\(\left(\text{Given: }k=\dfrac{4\pi^2}{GM_E}=1.33\times10^{-14}~\text{days}^{2}\text-\text{km}^{-3}\right)\)
1. \(17.3\) days
2. \(33.7\) days
3. \(27.3\) days
4. \(4\) days
\(\left(\text{Given: }k=\dfrac{4\pi^2}{GM_E}=1.33\times10^{-14}~\text{days}^{2}\text-\text{km}^{-3}\right)\)
1. \(17.3\) days
2. \(33.7\) days
3. \(27.3\) days
4. \(4\) days
Subtopic: Satellite |
66%
Level 2: 60%+
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A \(400~\text{kg}\) satellite is in a circular orbit of radius \(2R_E\) (where \(R_E\) is the radius of the earth) about the Earth. How much energy is required to transfer it to a circular orbit of radius \(4R_E ~?\)
(given: \(R_E=6.4\times10^{6}~\text{m}\) )
(given: \(R_E=6.4\times10^{6}~\text{m}\) )
| 1. | \(3.13\times10^{9}~\text{J}\) | 2. | \(3.13\times10^{10}~\text{J}\) |
| 3. | \(4.13\times10^{9}~\text{J}\) | 4. | \(4.13\times10^{8}~\text{J}\) |
Subtopic: Satellite |
59%
Level 3: 35%-60%
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A \(400~\text{kg}\) satellite is in a circular orbit of radius \(2R_E\) about the Earth. What are the changes in the kinetic and potential energies respectively to transfer it to a circular orbit of radius \(4R_{E}.\) (where \(R_E\) is the radius of the Earth)
1. \(3.13\times 10^{9}~\text{J}~\text{and}~6.25\times10^{9}~\text{J}\)
2. \(3.13\times 10^{9}~\text{J}~\text{and}~-6.25\times10^{9}~\text{J}\)
3. \(-3.13\times 10^{9}~\text{J}~\text{and}~-6.25\times10^{9}~\text{J}\)
4. \(-3.13\times 10^{8}~\text{J}~\text{and}~-6.25\times10^{8}~\text{J}\)
1. \(3.13\times 10^{9}~\text{J}~\text{and}~6.25\times10^{9}~\text{J}\)
2. \(3.13\times 10^{9}~\text{J}~\text{and}~-6.25\times10^{9}~\text{J}\)
3. \(-3.13\times 10^{9}~\text{J}~\text{and}~-6.25\times10^{9}~\text{J}\)
4. \(-3.13\times 10^{8}~\text{J}~\text{and}~-6.25\times10^{8}~\text{J}\)
Subtopic: Satellite |
Level 4: Below 35%
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- 1(current)
Q. No.
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