- 1(current)
Q. No.The peak voltage of the AC source is equal to:
| 1. | \(1 / \sqrt{2}\) times the rms value of the AC source |
| 2. | the value of voltage supplied to the circuit |
| 3. | the rms value of the AC source |
| 4. | \(\sqrt{2}\) times the rms value of the AC source |
Subtopic: RMS & Average Values |
76%
From NCERT
NEET - 2022
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A standard filament lamp consumes \(100\) W when connected to \(200\) V AC mains supply. The peak current through the bulb will be:
1. \(0.707\) A
2. \(1\) A
3. \(1.414\) A
4. \(2\) A
1. \(0.707\) A
2. \(1\) A
3. \(1.414\) A
4. \(2\) A
Subtopic: RMS & Average Values |
71%
From NCERT
NEET - 2022
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
A \(40\) F capacitor is connected to a \(200\) V, \(50\) Hz AC supply. The rms value of the current in the circuit is, nearly:
1. \(2.05\) A
2. \(2.5\) A
3. \(25.1\) A
4. \(1.7\) A
Subtopic: RMS & Average Values |
70%
From NCERT
NEET - 2020
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
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Links
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- 1(current)
Q. No.
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