An SHM has an amplitude \(a\) and  a time period \(T.\) The maximum velocity will be:
1. \({4a \over T}\)       
2.  \({2a \over T}\)
3. \({2 \pi \over T}\)
4. \({2a \pi \over T}\)  

Subtopic:  Simple Harmonic Motion |
 90%
From NCERT
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A particle is executing simple harmonic motion with frequency f. The frequency at which its kinetic energy changes into potential energy, will be:

1.   f/2         

2.  f

3.   2 f        

4.  4 f

Subtopic:  Energy of SHM |
 60%
From NCERT
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In a simple pendulum, the period of oscillation \(T\) is related to length of the pendulum \(L\) as:
1. \(\frac{L}{T}= \text{constant}\)
2. \(\frac{L^2}{T}= \text{constant}\)
3. \(\frac{L}{T^2}= \text{constant}\)
4. \(\frac{L^2}{T^2}= \text{constant}\)
Subtopic:  Angular SHM |
 84%
From NCERT
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A pendulum has time period T. If it is taken on to another planet having acceleration due to gravity half and mass 9 times that of the earth, then its time period on the other planet will be:

1. \(\sqrt{\mathrm{T}} \) 2. \(T \)
3. \(\mathrm{T}^{1 / 3} \) 4. \(\sqrt{2} \mathrm{~T}\)
Subtopic:  Angular SHM |
 82%
From NCERT
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A simple pendulum hanging from the ceiling of a stationary lift has a time period \(T_1\). When the lift moves downward with constant velocity, then the time period becomes \(T_2\). It can be concluded that: 
1. \(T_2 ~\text{is infinity} \) 2. \(T_2>T_1 \)
3. \(T_2<T_1 \) 4. \(T_2=T_1\)
Subtopic:  Angular SHM |
 61%
From NCERT
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If the length of a pendulum is made 9 times and mass of the bob is made 4 times, then the value of time period will become:

1. 3T

2. 3/2T

3. 4T

4. 2T

Subtopic:  Angular SHM |
 82%
From NCERT
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Two simple harmonic motions of angular frequency 100 rad s -1 and 1000 rad s-1 have the same displacement amplitude. The ratio of their maximum acceleration will be:
1. 1:10
2. 1:102
3. 1:103                               
4. 1:104

Subtopic:  Linear SHM |
 86%
From NCERT
NEET - 2008
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Which one of the following equations of motion represents simple harmonic motion? (where \(k\)\(k_0\)\(k_1\) and  α  are all positive.)
1. Acceleration = -k0x+k1x2\(k_0\)  
2. Acceleration = -kx+a
3. Acceleration = kx+a
4. Acceleration = kx

Subtopic:  Simple Harmonic Motion |
 72%
From NCERT
NEET - 2009
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A body performs simple harmonic motion about x=0 with an amplitude a and a time period T. The speed of the body at x=a2 will be:
1. πa32T                                         
2. πaT
3. 3π2aT                                           
4. πa3T

Subtopic:  Linear SHM |
 77%
From NCERT
NEET - 2009
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The displacement of a particle along the x-axis is given by x=asin2 ωt. The motion of the particle corresponds to:

1.  simple harmonic motion of frequency ω / π.
2.  simple harmonic motion of frequency  3 ω / 2 π.
3.  non-simple harmonic motion.
4.  simple harmonic motion of frequency ω / 2 π.
Subtopic:  Simple Harmonic Motion |
From NCERT
NEET - 2010
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