A particle is attached to a vertical spring and pulled down a distance of 0.01 m below its mean position and released. If its initial acceleration is 0.16 $\mathrm{m}/{\mathrm{s}}^{2}$, then its time period in seconds will be:

1. $\mathrm{\pi}$

2. $\frac{\mathrm{\pi}}{2}$

3. $\frac{\mathrm{\pi}}{4}$

4. $2\mathrm{\pi}$

Subtopic: Spring mass system |

88%

From NCERT

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The time period of the spring-mass system depends upon:

1. | the gravity of the earth | 2. | the mass of the block |

3. | spring constant | 4. | both (2) & (3) |

Subtopic: Spring mass system |

88%

From NCERT

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The frequency of a spring is \(n\) after suspending mass \(M.\) Now, after mass \(4M\) mass is suspended from the spring, the frequency will be:

1. | \(2n\) | 2. | \(n/2\) |

3. | \(n\) | 4. | none of the above |

Subtopic: Spring mass system |

80%

From NCERT

AIPMT - 1998

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The time periods for the figures (a) and (b) are ${\mathrm{T}}_{1}$ $\mathrm{and}$ ${\mathrm{T}}_{2}$ respectively. If all surfaces shown below are smooth, then the ratio $\frac{{\mathrm{T}}_{1}}{{\mathrm{T}}_{2}}$ will be:

1. 1: $\sqrt{3}$

2. 1: 1

3. 2: 1

4. $\sqrt{3}$: 2

Subtopic: Spring mass system |

81%

From NCERT

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The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it, another mass M is also suspended, the period of oscillation will now be:

1. T

2. T/$\sqrt{2}$

3. 2T

4. $\sqrt{2}$T

Subtopic: Spring mass system |

78%

From NCERT

AIPMT - 2010

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A spring having a spring constant of \(1200\) N/m is mounted on a horizontal table as shown in the figure. A mass of \(3\) kg is attached to the free end of the spring. The mass is then pulled sideways to a distance of \(2.0\) cm and released. The frequency of oscillations will be:

1. | \(3.0~\text{s}^{-1}\) | 2. | \(2.7~\text{s}^{-1}\) |

3. | \(1.2~\text{s}^{-1}\) | 4. | \(3.2~\text{s}^{-1}\) |

Subtopic: Spring mass system |

72%

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One end of a spring of force constant \(\mathrm{k}\) is fixed to a vertical wall and the other to a block of mass \(\mathrm{m}\) resting on a smooth horizontal surface. There is another wall at a distance ${\mathrm{x}}_{0}$ from the block. The spring is then compressed by $2{\mathrm{x}}_{0}$ and then released. The time taken to strike the wall will be?

1. | \({1 \over 6} \pi \sqrt{ {k \over m}}\) | 2. | \( \sqrt{ {k \over m}}\) |

3. | \({2 \pi \over 3} \sqrt{ {m \over k}}\) | 4. | \({ \pi \over 4} \sqrt{ {k \over m}}\) |

Subtopic: Spring mass system |

72%

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The time period of a mass suspended from a spring is T. If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be:

1. T/4

2. T

3. T/2

4. 2T

Subtopic: Spring mass system |

72%

From NCERT

AIPMT - 2003

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An ideal spring with spring-constant *K* is hung from the ceiling and a block of mass *M* is attached to its lower end. The mass is released with the spring initially un-stretched. Then the maximum extension in the spring will be:

1. 4 *Mg/K*

2. 2* Mg/K*

3. *Mg/K*

4. *Mg/*2*K*

Subtopic: Spring mass system |

56%

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A spring elongates by a length 'L' when a mass 'M' is suspended to it. Now a tiny mass 'm' is attached to the mass 'M' and then released. The new time period of oscillation will be:

1. \(2 \pi \sqrt{\frac{\left(\right. M + m \left.\right) l}{Mg}}\)

2. \(2 \pi \sqrt{\frac{ml}{Mg}}\)

3. \(2 \pi \sqrt{L / g}\)

4. \(2 \pi \sqrt{\frac{Ml}{\left(\right. m + M \left.\right) g}}\)

Subtopic: Spring mass system |

59%

From NCERT

AIPMT - 1999

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