# The time period of the spring-mass system depends upon: 1. the gravity of the earth 2. the mass of the block 3. spring constant 4. both (2) & (3)

Subtopic:  Spring mass system |
88%
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Acceleration of the particle at s from the given displacement (y) versus time (t) graph will be?

1. $\frac{\sqrt{3}{\mathrm{\pi }}^{2}}{4}$ $cm/{s}^{2}$

2. $-\frac{\sqrt{3}{\mathrm{\pi }}^{2}}{4}$ $cm/{s}^{2}$

3. $-{\mathrm{\pi }}^{2}$ $\mathrm{cm}/{\mathrm{s}}^{2}$

4. Zero

Subtopic:  Linear SHM |
From NCERT
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A simple pendulum attached to the ceiling of a stationary lift has a time period of 1 s. The distance y covered by the lift moving downward varies with time as y = 3.75 ${\mathrm{t}}^{2}$, where y is in meters and t is in seconds. If g = 10 $\mathrm{m}/{\mathrm{s}}^{2}$, then the time period of the pendulum will be:

 1 4 s 2 6 s 3 2 s 4 12 s
Subtopic:  Types of Motion | Simple Harmonic Motion | Angular SHM |
61%
From NCERT
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The graph between the velocity (v) of a particle executing S.H.M. and its displacement (x) is shown in the figure. The time period of oscillation for this SHM will be

1.  $\sqrt{\frac{\mathrm{\alpha }}{\mathrm{\beta }}}$

2.  $2\mathrm{\pi }\sqrt{\frac{\mathrm{\alpha }}{\mathrm{\beta }}}$

3.  $2\mathrm{\pi }\left(\frac{\mathrm{\beta }}{\mathrm{\alpha }}\right)$

4.  $2\mathrm{\pi }\left(\frac{\mathrm{\alpha }}{\mathrm{\beta }}\right)$

Subtopic:  Simple Harmonic Motion |
64%
From NCERT
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A particle executes SHM with a time period of 4 s. The time taken by the particle to go directly from its mean position to half of its amplitude will be:

1.  $\frac{1}{3}$ s

2.  1 s

3.  $\frac{1}{2}$ s

4.   2 s

Subtopic:  Linear SHM |
75%
From NCERT
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Two simple pendulums of length 1 m and 16 m are in the same phase at the mean position at any instant. If T is the time period of the smaller pendulum, then the minimum time after which they will again be in the same phase will be:

1.  $\frac{3\mathrm{T}}{2}$

2.  $\frac{3\mathrm{T}}{4}$

3.  $\frac{2\mathrm{T}}{3}$

4.  $\frac{4\mathrm{T}}{3}$

Subtopic:  Angular SHM |
From NCERT
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A particle executes linear SHM between $$x=A.$$ The time taken to go from $$0$$ to $$A/2$$ is ${\mathrm{T}}_{1}$ and to go from $$A/2$$ to $$A$$ is ${\mathrm{T}}_{2}$, then:

 1 ${\mathrm{T}}_{1}$ $<$ 2 ${\mathrm{T}}_{1}$ $>$ ${\mathrm{T}}_{2}$ 3 ${\mathrm{T}}_{1}$ $=$ ${\mathrm{T}}_{2}$ 4 ${\mathrm{T}}_{1}$ $=$ $2{\mathrm{T}}_{2}$
Subtopic:  Linear SHM |
71%
From NCERT
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Force on a particle F varies with time t as shown in the given graph. The displacement x vs time t graph corresponding to the force-time graph will be:

 1 2 3 4
Subtopic:  Linear SHM |
66%
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The displacement $$x$$ of a particle varies with time $$t$$ as $$x = A sin\left (\frac{2\pi t}{T} +\frac{\pi}{3} \right)$$$\mathrm{}$The time taken by the particle to reach from $$x = \frac{A}{2}$$ to $$x = -\frac{A}{2}$$ will be:

 1 $$\frac{T}{2}$$ 2 $$\frac{T}{3}$$ 3 $$\frac{T}{12}$$ 4 $$\frac{T}{6}$$

Subtopic:  Phasor Diagram |
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Equation of a simple harmonic motion is  given by x = asin$\mathrm{\omega }$t. For which value of x, kinetic energy is equal to the potential energy?

1.  $\mathrm{x}$ $=$ $±$ $\mathrm{a}$

2.  $\mathrm{x}$ $=$ $±$ $\frac{\mathrm{a}}{2}$

3.  $\mathrm{x}$ $=$ $±$ $\frac{\mathrm{a}}{\sqrt{2}}$

4.  $\mathrm{x}$ $=$ $±$ $\frac{\sqrt{3}\mathrm{a}}{2}$

Subtopic:  Energy of SHM |
82%
From NCERT
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