In simple harmonic motion, the ratio of acceleration of the particle to its displacement at any time is a measure of:

1. Spring constant 2. Angular frequency
3. (Angular frequency)2  4. Restoring force

Subtopic:  Simple Harmonic Motion |
 81%
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One end of a spring of force constant \(\mathrm{k}\) is fixed to a vertical wall and the other to a block of mass \(\mathrm{m}\) resting on a smooth horizontal surface. There is another wall at a distance x0 from the block. The spring is then compressed by 2x0 and then released. The time taken to strike the wall will be?

          

1. \({1 \over 6} \pi \sqrt{ {k \over m}}\) 2. \( \sqrt{ {k \over m}}\)
3. \({2 \pi \over 3} \sqrt{ {m \over k}}\) 4. \({ \pi \over 4} \sqrt{ {k \over m}}\)
Subtopic:  Spring mass system |
 72%
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When the displacement is half the amplitude in an SHM, the ratio of potential energy to the total energy is:
1. 1 / 2

2. 1 / 4

3. 1

4. 1 / 8

Subtopic:  Energy of SHM |
 81%
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A block is connected to a relaxed spring and kept on a smooth floor. The block is given a velocity towards the right. Just after this:
               

1. the speed of block starts decreasing but acceleration starts increasing.
2. the speed of the block as well as its acceleration starts decreasing.
3. the speed of the block starts increasing but its acceleration starts decreasing.
4. the speed of the block as well as acceleration start increasing.

Subtopic:  Spring mass system |
 59%
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The amplitude and the time period in an S.H.M. are 0.5 cm and 0.4 sec respectively. If the initial phase is π/2 radian, then the equation of S.H.M. will be:

1. y=0.5sin5πt

2. y=0.5sin4πt

3. y=0.5sin2.5πt

4. y=0.5cos5πt

Subtopic:  Linear SHM |
 69%
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A mass m is suspended from two springs of spring constant k1 and k2 as shown in the figure below. The time period of vertical oscillations of the mass will be
                

1. 2πk1+k2m

2. 2πmk1+k2

3. 2πm(k1k2)k1+k2

4. 2πmk1+k2k1k2

Subtopic:  Combination of Springs |
 77%
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Kinetic energy of a particle executing simple harmonic motion in straight line is \(pv^2\) and potential energy is \(qx^2,\) where \(v\) is speed at distance \(x\) from the mean position. The time period of the SHM is given by the expression:

1. 2πqp

2. 2πpq

3. 2πqp+q

4. 2πpp+q

Subtopic:  Energy of SHM |
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A simple pendulum of mass m swings about point B between extreme positions A and C. Net force acting on the bob at these three points is correctly shown by:

1. 2.
3. 4.
Subtopic:  Angular SHM |
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The potential energy of a particle oscillating along the x-axis is given as U = 20+ (x–2)2 where U is in joules and x in meters. The total mechanical energy of the particle is 36 J. The maximum kinetic energy of the particle will be:
1. 24 J 

2. 36 J

3. 16 J 

4. 20 J

Subtopic:  Energy of SHM |
 65%
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A particle is executing SHM according to y = a cosωt. Then, which of the following graphs represent variations of potential energy?
             
1. I and III

2. II and IV

3. II and III

4. I and IV

Subtopic:  Energy of SHM |
 59%
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