The net magnetic flux through any closed surface, kept in uniform magnetic field is:

1. | zero | 2. | \(\dfrac{\mu_{0}}{4 \pi}\) |

3. | \(4\pi μ_{0}\) | 4. | \(\dfrac{4\mu_{0}}{\pi}\) |

Subtopic: Magnetic Flux |

94%

From NCERT

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A circular disc of radius \(0.2\) m is placed in a uniform magnetic field of induction \(\frac{1}{\pi} \left(\frac{\text{Wb}}{\text{m}^{2}}\right)\) in such a way that its axis makes an angle of \(60^{\circ}\) with \(\vec {B}.\) The magnetic flux linked to the disc will be:

1. | \(0.02\) Wb | 2. | \(0.06\) Wb |

3. | \(0.08\) Wb | 4. | \(0.01\) Wb |

Subtopic: Magnetic Flux |

86%

From NCERT

NEET - 2008

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If a current is passed through a circular loop of radius \(R\) then magnetic flux through a coplanar square loop of side \(l\) as shown in the figure \((l<<R)\) is:

1. | \(\frac{\mu_{0} l}{2} \frac{R^{2}}{l}\) | 2. | \(\frac{\mu_{0} I l^{2}}{2 R}\) |

3. | \(\frac{\mu_{0} l \pi R^{2}}{2 l}\) | 4. | \(\frac{\mu_{0} \pi R^{2} I}{l}\) |

Subtopic: Magnetic Flux |

82%

From NCERT

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The radius of a loop as shown in the figure is \(10~\text{cm}.\) If the magnetic field is uniform and has a value \(10^{-2}~ \text{T},\) then the flux through the loop will be:

1. | \(2 \pi \times 10^{-2}~\text{Wb}\) | 2. | \(3 \pi \times 10^{-4}~\text{Wb}\) |

3. | \(5 \pi \times 10^{-5}~\text{Wb}\) | 4. | \(5 \pi \times 10^{-4}~\text{Wb}\) |

Subtopic: Magnetic Flux |

76%

From NCERT

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A square of side \(L\) meters lies in the \(XY\text-\)plane in a region where the magnetic field is given by \(\vec{B}=B_{0}\left ( 2\hat{i} +3\hat{j}+4\hat{k}\right )\text{T}\) where \(B_{0}\) is constant. The magnitude of flux passing through the square will be:

1. \(2 B_{0} L^{2}~\text{Wb}\)

2. \(3 B_{0} L^{2}~\text{Wb}\)

3. \(4 B_{0} L^{2}~\text{Wb}\)

4. \(\sqrt{29} B_{0} L^{2}~\text{Wb}\)$$

Subtopic: Magnetic Flux |

72%

From NCERT

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What is the dimensional formula of magnetic flux?

1. \(\left[ M L^2 T^{-2}A^{-1}\right]\)

2. \(\left[ M L^1 T^{-1}A^{-2}\right]\)

3. \(\left[ M L^2 T^{-3}A^{-1}\right]\)

4. \(\left[ M L^{-2} T^{-2}A^{-2}\right]\)$$

Subtopic: Magnetic Flux |

72%

From NCERT

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A square loop of side \(1\) m and resistance \(1\) \(\Omega\) is placed in a magnetic field of \(0.5\) T. If the plane of the loop is perpendicular to the direction of the magnetic field, the magnetic flux through the loop is:

1. | \(0\) | 2. | \(2\) weber |

3. | \(0.5\) weber | 4. | \(1\) weber |

Subtopic: Magnetic Flux |

66%

From NCERT

NEET - 2022

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A circular loop of radius \(R\) carrying current \(i\) lies in the \(x\text-y\) plane. If the centre of the loop coincides with the origin, then the total magnetic flux passing through the \(x\text-y\) plane will be:

1. | directly proportional to \(i\). |

2. | directly proportional to \(R\). |

3. | directly proportional to \(R^2\). |

4. | Zero. |

Subtopic: Magnetic Flux |

58%

From NCERT

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