- 1(current)
Q. No.A circular coil \(\mathrm{ABCD}\) carrying a current \(i\) is placed in a uniform magnetic field. If the magnetic force on the segment \(\mathrm{AB}\) is \(\vec{F},\) then the force on the remaining segment \(\mathrm{BCDA}\) is:
1. \(-\vec{F}\)
2. \(3\vec{F}\)
3. \(-3\vec{F}\)
4. \(\vec{F}\)
1. \(-\vec{F}\)
2. \(3\vec{F}\)
3. \(-3\vec{F}\)
4. \(\vec{F}\)
Subtopic: Â Current Carrying Loop: Force & Torque |
 75%
From NCERT
NEET - 2013
Please attempt this question first.
Hints
Please attempt this question first.
A circular loop of area \(1\) cm2, carrying a current of \(10\) A, is placed in a magnetic field of \(0.1\) T perpendicular to the plane of the loop. The torque on the loop due to the magnetic field is:
1. zero
2. \(10^{-4}\) N-m
3. \(10^{-2}\) N-m
4. \(1\) N-m
Subtopic: Â Current Carrying Loop: Force & Torque |
 53%
From NCERT
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
- 1(current)
Q. No.
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