A cup of coffee cools from $$90^{\circ}\mathrm{C}$$ $\mathrm{to}$ $$80~^{\circ}\mathrm{C}$$ in t minutes, when the room temperature is $$20^{\circ}\mathrm{C}$$$\mathrm{}$. The time taken by a similar cup of coffee to cool from $$80^{\circ}\mathrm{C}$$ $\mathrm{to}$ $$60^{\circ}\mathrm{C}$$ at room temperature same at $$20^{\circ}\mathrm{C}$$ is:
1. $$\frac{10}{13}t$$
2. $$\frac{5}{13}t$$
3. $$\frac{13}{10}t$$
4. $$\frac{13}{5}t$$

Subtopic: Â Newton's Law of Cooling |
Â 62%
From NCERT
NEET - 2021
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An object kept in a large room having an air temperature of $$25^\circ \text{C}$$ takes $$12$$ minutes to cool from $$80^\circ \text{C}$$ to $$70^\circ \text{C}.$$ The time taken to cool for the same object from $$70^\circ \text{C}$$ to $$60^\circ \text{C}$$ would be nearly:
1. $$10$$ min
2. $$12$$ min
3. $$20$$ min
4. $$15$$ min

Subtopic: Â Newton's Law of Cooling |
Â 77%
From NCERT
NEET - 2019
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A body cools from a temperature of $$3T$$ to $$2T$$ in $$10$$ minutes. The room temperature is $$T$$. Assuming that Newton's law of cooling is applicable, the temperature of the body at the end of the next $$10$$ minutes will be:

 1 $$\frac{7}{4}T$$ 2 $$\frac{3}{2}T$$ 3 $$\frac{4}{3}T$$ 4 $$T$$

Subtopic: Â Newton's Law of Cooling |
Â 72%
From NCERT
NEET - 2016
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A certain quantity of water cools from $$70~^{\circ}\text{C}$$ to $$60~^{\circ}\text{C}$$ in the first $$5$$ minutes and to $$54~^{\circ}\text{C}$$ in the next $$5$$ minutes. The temperature of the surroundings is:
1. $$45~^{\circ}\text{C}$$
2. $$20~^{\circ}\text{C}$$
3. $$42~^{\circ}\text{C}$$
4. $$10~^{\circ}\text{C}$$

Subtopic: Â Newton's Law of Cooling |
Â 76%
From NCERT
AIPMT - 2014
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