- 1(current)
Q. No.The potential energy of a particle in a force field is \(U=\dfrac{A}{r^2}-\dfrac{B}{r}\) where \(A\) and \(B\) are positive constants and \(r\) is the distance of the particle from the centre of the field. For stable equilibrium, the distance of the particle is:
| 1. | \(\dfrac{B}{A}\) | 2. | \(\dfrac{B}{2A}\) |
| 3. | \(\dfrac{2A}{B}\) | 4. | \(\dfrac{A}{B}\) |
Subtopic: Â Potential Energy: Relation with Force |
 79%
From NCERT
AIPMT - 2012
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