A thin convex lens made from crown glass \((\mu=3/2)\) has focal length \(f.\) When it is measured in two different liquids having refractive indices \(4/3\) and \(5/3\), it has the focal lengths \(f_1\) and \(f_2\) respectively. The correct relation between the focal lengths is:
| 1. | \(f_1>f \) and \(f_2\) becomes negative |
| 2. | \(f_2>f\) and \(f_1\) becomes negative |
| 3. | \(f_1\) and \(f_2\) becomes negative |
| 4. | \(f_1=f_2<f \) |

A plano-convex lens and a plano-concave lens, which have the same radius of curvature \(R\) but are made of different materials, are placed side by side as shown in the figure. If the refractive index of the material of lens-\(1\) is \(\mu_1\)β and that of lens-\(2\) is \(\mu_2, \) the focal length of the combined system is:

| 1. | \( \dfrac{R}{2-\left(\mu_1-\mu_2\right)} \) | 2. | \( \dfrac{R}{2\left(\mu_1-\mu_2\right)} \) |
| 3. | \( \dfrac{R}{\left(\mu_1-\mu_2\right)} \) | 4. | \( \dfrac{2 R}{\left(\mu_1-\mu_2\right)}\) |
| 1. | \(10~\text{cm}\) | 2. | \(20~\text{cm}\) |
| 3. | \(30~\text{cm}\) | 4. | \(40~\text{cm}\) |
A plano-convex lens of focal length \({f_2},\) refractive index \(\mu_2,\) and radius of curvature \({R}\) fits exactly into a plano-concave lens of focal length \({f_1},\) refractive index \(\mu_1,\) and the same radius of curvature \({R}.\) The plane faces of the two lenses are parallel and in contact. The focal length of the combined system is:
| 1. | \({f_1-f_2}\) | 2. | \(\dfrac{R}{ (\mu_2-\mu_1)}\) |
| 3. | \(\dfrac{2f_1f_2}{( \mu_2-\mu_1)}\) | 4. | \({f_1+f_2}\) |