Q. No.When acidified the solution is added to Sn++ salt then Sn++ changes to
1.
Sn
2.
Sn3+
3.
Sn4+
4.
Sn+
Highest oxidation state of manganese in fluoride is +4(Mn) but highest oxidation state in oxides is +7() because
| 1. | Fluorine is more electronegative than oxygen |
| 2. | Fluorine does not possess d orbitals |
| 3. | Fluorine stabilises lower oxidation state |
| 4. | In covalent compounds, fluorine can form single bond only while oxygen forms double bond |
Although zirconium belongs to 4d transition series and hafnium to 5d transition series even then they show similar physical and chemical properties because............. .
| 1. | Both belong to d-block |
| 2. | Both have same number of electrons |
| 3. | Both have similar atomic radius |
| 4. | Both belong to the same group of the Periodic Table |
Why is HCl not used to make the medium acidic in oxidation reactions of in acidic medium?
| 1. | Both HCl and KMnO4 act as oxidising agents |
| 2. | KMnO4 oxidises HCl into Cl2, which is also an oxidising agent |
| 3. | KMnO4 is a weaker oxidising agent than HCl |
| 4. | KMnO4 acts as a reducing agent in the presence of HCl |
Match Column I (Catalyst) with Column II (Process), and mark the appropriate option:
| Column I - (Catalyst) | Column II - (Process) | ||
| A. | Ni in the presence of hydrogen | 1. | Contact process |
| B. | Cu2Cl2 | 2. | Vegetable oil to ghee |
| C. | V2O5 | 3. | Sandmeyer reaction |
| D. | Finely divided iron | 4. | Haber's process |
| 5. | Decomposition of KClO3 |
Codes:
| A | B | C | D | |
| 1. | 3 | 4 | 2 | 5 |
| 2. | 2 | 3 | 1 | 4 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |
Match Compound/element in Column-I with uses in Column-II and select the best match from the codes given:
| Column-I (Compound/element) |
Column-II (Uses) |
||
| A. | Lanthanoid oxide | I. | Petroleum cracking |
| B. | Lanthanoid | II. | Television screen |
| C. | Mischmetal | III. | Lanthanoid metal + iron |
| D. | Mixed oxides of lanthanoids are employed | IV. | Production of iron alloy |
| Options: | A | B | C | D |
| 1. | II | I | IV | III |
| 2. | I | II | III | IV |
| 3. | II | IV | III | I |
| 4. | IV | I | III | II |
Match the properties given in Column I with uses given in Column II
| Column I-(Property) | Column II-(Metal) | ||
| A. | An element that can show +8 oxidation state | 1. | Mn |
| B. | 3d block element that can show up to +7 | 2. | Cr |
| C. | 3d block element with the highest melting point | 3. | Os |
| 4. | Fe | ||
| A | B | C | |
| 1. | 3 | 1 | 2 |
| 2. | 1 | 2 | 3 |
| 3. | 1 | 4 | 3 |
| 4. | 4 | 2 | 3 |
Match the statements given in Column I with the oxidation states given in Column and mark the correct option.
| Column I | Column II | ||
| A. | Oxidation state of Mn in \(\mathrm{MnO}_2\) is | 1. | +2 |
| B. | Most stable oxidation state of Mn is | 2. | +3 |
| C. | Most stable oxidation state of Mn in oxides is | 3. | +4 |
| D. | Characteristic oxidation state of lanthanoids is | 4. | +5 |
| 5. | +7 |
| Options: | A | B | C | D |
| 1. | 2 | 3 | 4 | 1 |
| 2. | 3 | 1 | 5 | 2 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |
Match the solutions given in Column I with the colours given in Column II.
| Column I (Aqueous solution of salt) |
Column II (Colour) |
||
| A. | FeSO4 .7H2O | 1. | Green |
| B. | NiCl2 . 4H2O | 2. | Light pink |
| C. | MnCl2.4H2O | 3. | Blue |
| D. | CoCl2. 6H2O | 4. | Pale green |
| 5. | Pink |
Codes:
| A | B | C | D | |
| 1. | 2 | 3 | 4 | 1 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 1 | 2 | 5 |
Match the property given in Column-I with the element given in Column-II.
|
Column-I (Property) |
Column-II (Element) |
||
| A. |
Lanthanoid which shows + 4 oxidation state |
1. |
Pm |
| B. |
Radioactive lanthanoid |
2. |
Ce |
| C. |
Lanthanoid which has 4 electronic configurations in +3 oxidation state |
3. |
Lu |
| D. |
Lanthanoid which has 4 electronic configurations in +3 oxidation state |
4. |
Gd |
| Options: | A | B | C | D |
| 1. | 2 | 4 | 1 | 3 |
| 2. | 1 | 2 | 3 | 4 |
| 3. | 2 | 1 | 4 | 3 |
| 4. | 4 | 1 | 3 | 2 |
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