Q. No.Consider the given reaction and products:
The correct statement about the given chemical reaction is :
1. -NH2 group is ortho and para directive, so product (B) is not possible.
2. Reaction is possible and compound (B) will be the major product.
3. The reaction will form sulphonated product instead of nitration.
4. Reaction is possible and compound (A) will be major product.
In the following reaction, the reason why meta-nitro product also formed is:
1. Low temperature
2. –NH2 group is highly meta-directive
3. Formation of anilinium ion
4. –NO2 substitution always takes place at meta-position
Which of the following option contains the correct structure?
| 1. | A is  |
2. | B is  |
| 3. | C is  |
4. | D is  |
The correct order of the set of reagents for the above conversion is:
| 1. | \(\mathrm{Br}_2 \mid \mathrm{FeBr}_3, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}\) |
| 2. | \(\mathrm{H}_2 \mathrm{SO}_4, \mathrm{Ac}_2 \mathrm{O}, \mathrm{Br}_2, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}\) |
| 3. | \(\mathrm{Ac}_2 \mathrm{O}, \mathrm{Br}_2, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}\) |
| 4. | \(\mathrm{Ac}_2 \mathrm{O}, \mathrm{H}_2 \mathrm{SO}_4, \mathrm{Br}_2, \mathrm{NaOH}\) |
| Assertion (A): | Experimental reaction of CH₃Cl with aniline and anhydrous AlCl₃ does not give o- and p-methylaniline. |
| Reason (R): | The −NH₂ group of aniline forms a complex with anhydrous AlCl₃, which reduces its electron-donating ability and makes it a deactivating, meta-directing group. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A) |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A) |
| 3. | (A) is True, but (R) is False |
| 4. | (A) is False, but (R) is True |
| 1. | 27 | 2. | 24 |
| 3. | 26 | 4. | 22 |
Find the melting point of product C obtained by decarboxylation of all six possible isomeric diaminobenzoic acids, C₆H₃(NH₂)₂COOH.
On decarboxylation, the six isomeric diaminobenzoic acids give three products, A, B, and C.
Three acids give product A, two acids give product B, and one acid gives product C.
1. \(\mathrm{63^\circ C}\)
2. \(\mathrm{90^\circ C}\)
3. \(\mathrm{104^\circ C}\)
4. \(\mathrm{142^\circ C}\)
| Statement I | Grignard reagent (R–MgX) reacts with CO₂ followed by acidification to form a carboxylic acid (R–COOH). This on heating with NH₃ forms an amide (R–CONH₂), which on treatment with NaOCl gives a primary amine (R–NH₂). The amine on reaction with CHCl₃/NaOH forms an isocyanide (R-NC). |
| Statement II | Isocyanide (R-NC) on hydrolysis gives Carboxylic acid (RCOOH). |
Choose the correct option:
| 1. | Statement-I and Statement-II both are correct |
| 2. | Statement-I is incorrect Statement-II is correct |
| 3. | Statement-I is correct Statement-II is incorrect |
| 4. | Statement-I and Statement-II both incorrect |
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