| 1. | A and B only | 2. | B and C only |
| 3. | A and C only | 4. | A only |
BF3 is a planar and an electron deficient compound. Hybridization and number of electrons around the central atom, respectively are:
| 1. | sp2 and 6 | 2. | sp2 and 8 |
| 3. | sp3 and 4 | 4. | sp3 and 6 |
Match the shape of molecules in Column I with the type of hybridization in Column II.
|
Column I |
Column II |
||
| A. |
Tetrahedral |
1. |
sp2 |
| B. |
Trigonal |
2. |
sp |
| C. |
Linear |
3. |
sp3 |
Codes:
| Options: | A | B | C |
| 1. | 3 | 1 | 2 |
| 2. | 1 | 2 | 3 |
| 3. | 5 | 4 | 3 |
| 4. | 4 | 5 | 3 |
Match the species in Column I with the shape in Column II.
|
Column I |
Column II |
||
| A. |
H3O+ |
1. |
Linear |
| B. |
HCCH |
2. |
Angular |
| C. |
ClO2- |
3. |
Tetrahedral |
| D. |
NH4+ |
4. |
Trigonal bipyramidal |
| 5. |
Pyramidal |
Codes:
| Options: | A | B | C | D |
| 1. | 5 | 1 | 2 | 3 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |
Match the species in Column I with the type of hybrid orbitals in Column II.
|
Column I |
Column II |
||
| A. |
SF4 |
1. |
sp3d2 |
| B. |
IF5 |
2. |
d2sp3 |
| C. |
NO2+ |
3. |
sp3d |
| D. |
NH4+ |
4. |
sp3 |
| 5. |
sp |
Codes:
| Options: | A | B | C | D |
| 1. | 3 | 1 | 5 | 4 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |
The correct bond angle for \(\mathrm{sp}^2\) hybridization is:
1. \(90^\circ\)
2. \(120^\circ\)
3. \(180^\circ\)
4. \(109^\circ\)
Which of the following species have the same shape?
| (a) | CO2 | (b) | CCl4 |
| (c) | O3 | (d) | NO2– |
Choose the correct option
1. (a), (b)
2. (b), (c)
3. (c), (d)
4. (b), (d)
| List-I Molecule |
List-II Shape or geometry of the molecule |
|
| a. | PCl5 | Trigonal planar |
| b. | SF6 | Octahedral |
| c. | BeCl2 | Linear |
| d. | NH3 | Trigonal pyramidal |
| 1. | b | 2. | c |
| 3. | d | 4. | a |