Rings are rotated and translated in a uniform magnetic field as shown in the figure. Arrange the magnitude of emf induced across \(AB\):

| 1. | \(\mathrm{emf_{a}<emf_{b}<emf_{c}}\) |
| 2. | \(\mathrm{emf_{a}=emf_{b}<emf_{c}}\) |
| 3. | \(\mathrm{emf_{a}={emf}_{c}<{emf}_{b}}\) |
| 4. | \(\mathrm{emf_{a}<emf_{b}={emf}_{c}}\) |
| 1. | \(B\) | 2. | \(l\) |
| 3. | time, \(t\) | 4. | all of the above |

The wires \(\mathrm{P}_1\mathrm{Q}_1\) and \(\mathrm{P}_2\mathrm{Q}_2\) are made to slide on the rails with the same speed \(10~\text{m/s}\). If \(\mathrm{P}_1\mathrm{Q}_1\) moves towards the left and \(\mathrm{P}_2\mathrm{Q}_2\) moves towards the right, then the electric current in the \(19~\Omega\) resistor is:
1. zero
2. \(10~\text{mA}\)
3. \(0.1~\text{mA}\)
4. \(1~\text{mA}\)
| 1. | \(x\) | 2. | \(\sqrt{r^2-x^2}\) |
| 3. | \(r\) | 4. | \(x\sqrt{r^2-x^2}\) |

A conducting rod is rotated in a plane perpendicular to a uniform magnetic field with constant angular velocity. The correct graph between the induced emf \((e)\) across the rod and time \((t)\) is:
| 1. | 2. | ||
| 3. | 4. |
| Assertion (A): | The average induced electric field within the wire has a magnitude of \(\dfrac12B\omega L.\) |
| Reason (R): | The induced electric field is the motional EMF per unit length, and the motional EMF is \(\dfrac12B\omega L^2.\) |
| 1. | (A) is True but (R) is False. |
| 2. | (A) is False but (R) is True. |
| 3. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 4. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |