- 1(current)
Q. No.\(18\) cells each having the same EMF are connected in series with some cells being wrongly connected. This arrangement of battery is connected in series with an ammeter and two identical cells which are in series. Current of \(3~\text{A}\) is drawn when cells and battery support each other and current of \(2~\text{A}\) is drawn when cells and battery oppose each other. The number of wrongly connected cells is:
| 1. | \(1\) | 2. | \(2\) |
| 3. | \(3\) | 4. | \(4\) |
Subtopic: Grouping of Cells |
From NCERT
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Two batteries of emf \(\varepsilon_1\) and \(\varepsilon_2\) \((\varepsilon_2 > \varepsilon_1)\) respectively are connected in parallel as shown in the figure.
| 1. | The equivalent emf \(\varepsilon_{eq}\) of the two cells is between \(\varepsilon_1\) and \(\varepsilon_2\) i.e, \(\varepsilon_1<\varepsilon_{e q}<\varepsilon_2\) |
| 2. | The equivalent emf \(\varepsilon_{eq}\) is smaller than \(\varepsilon_1\) |
| 3. | The \(\varepsilon_{eq}\) is given by \(\varepsilon_{e q}=\varepsilon_1+\varepsilon_2\) always |
| 4. | \(\varepsilon_{eq}\) is independent of internal resistances \(r_1\) and \(r_2\) |
Subtopic: Grouping of Cells |
59%
From NCERT
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Two hundred cells of the same emf \(E\) and same internal resistance \(r\) are connected in series in the same order without external resistance. The potential drop across \(50\) cells is found to be:
1. \(50E\)
2. \(150E\)
3. \(200E\)
4. zero
1. \(50E\)
2. \(150E\)
3. \(200E\)
4. zero
Subtopic: Grouping of Cells |
From NCERT
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Two cells having emfs \(3\) V and \(2\) V are connected in parallel and they give an emf of \(0.5\) V in the same sense as \(3\) V \(-\) cell. The internal resistances of the cells are \(r_1\) and \(r_2\) respectively. If one cell is reversed, their combined emf becomes \(2.5\) V. The ratio of their internal resistances \(\Big(\dfrac{r_1}{r_2}\Big) \) is:
1. \(1\)
2. \(\dfrac12\)
3. \(\dfrac21\)
4. \(\sqrt2\)
1. \(1\)
2. \(\dfrac12\)
3. \(\dfrac21\)
4. \(\sqrt2\)
Subtopic: Grouping of Cells |
67%
From NCERT
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\(n\) identical cells, each with an EMF \(E\) and internal resistance \(r,\) are connected in series. An external resistance \(R\) is also connected in series with this combination, forming a closed circuit. The current through the external resistance \(R\) is:
| 1. | \(\dfrac{n E}{R+r}\) | 2. | \(\dfrac{n E}{n R+r}\) |
| 3. | \( \dfrac{n E}{R+n r}\) | 4. | \(\dfrac{E}{R+n r}\) |
Subtopic: Grouping of Cells |
77%
From NCERT
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A battery consists of a variable number \(n\) of identical cells having equal internal resistance connected in series. The terminals of the battery are short-circuited and the current \(I\) measured. Which one of the graphs below shows the correct relationship between \(I\) and \(n?\)
| 1. |  |
2. |  |
| 3. |  |
4. |  |
Subtopic: Grouping of Cells |
74%
From NCERT
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For the circuit shown in the figure, the current \(I\) will be:
| 1. | \(0.75~\text{A}\) | 2. | \(1~\text{A}\) |
| 3. | \(1.5~\text{A}\) | 4. | \(0.5~\text{A}\) |
Subtopic: Grouping of Cells |
82%
From NCERT
NEET - 2020
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