The current in a simple series circuit is \(5.0\) A. When an additional resistance of \(2.0\) \(\Omega\) is inserted, the current decreases to \(4.0\) A. The original resistance of the circuit was:
1. \(1.25\) \(\Omega\)
2. \(8\) \(\Omega\)
3. \(10\) \(\Omega\)
4. \(20\) \(\Omega\)
1. | \(52~ \Omega\) | 2. | \(55~ \Omega\) |
3. | \(60 ~\Omega\) | 4. | \(26~ \Omega\) |
Each branch in the following circuit has a resistance \(R\).
The equivalent resistance of the circuit between points \(A\) and \(B\) is:
1. | \(R\) | 2. | \(2R\) |
3. | \(4R\) | 4. | \(8R\) |
1. | \(1R\) | 2. | \({\dfrac35}R\) |
3. | \({\dfrac78}R\) | 4. | \({\dfrac58}R\) |
1. | \(I_4=\dfrac{24}{55}~\text{A},~\text{and} ~I_5 = \dfrac{96}{55}~\text{A}\) |
2. | \(I_4=\dfrac{96}{55}~\text{A},~\text{and} ~I_5 = \dfrac{24}{55}~\text{A}\) |
3. | \(I_4=\dfrac{24}{37}~\text{A},~\text{and}~ I_5 = \dfrac{96}{37}~\text{A}\) |
4. | \(I_4=\dfrac{96}{37}~\text{A},~\text{and} ~I_5 = \dfrac{24}{37}~\text{A}\) |
In the electrical network shown below, resistors are connected between points, \(P\) and \(Q.\) Each corner branch contains a resistance of \(2R,\) while the central horizontal branch contains two resistors of resistance \(r\) each. The vertical branch resistors also have a resistance of \(2R\) each.
1. | \(2 R r /(R+r)\) | 2. | \(8 R(R+r) /(3 R+r)\) |
3. | \((2r+4R)\) | 4. | \((5R/2+2r)\) |