Q. No.A capacitor of capacitance \(C\) is charged to a potential \(V.\) The flux of the electric field through a closed surface enclosing the capacitor is:
| 1. | \( \frac {CV} {\varepsilon_0}\) | 2. | \( \frac {2CV} {\varepsilon_0}\) |
| 3. | \( \frac {CV} {2\varepsilon_0}\) | 4. | zero |
The potential difference between \(A\) and \(B,\) after \(A\) is connected to \(Y\) and \(B\) to \(X,\) is:
1. \(2.6\) V
2. \(2.4\) V
3. \(6\) V
4. zero
The charge on the plates of the capacitor in a steady-state will be:
1. \(3~\mu\text{C}\)
2. \(9~\mu\text{C}\)
3. \(27~\mu\text{C}\)
4. \(36~\mu\text{C}\)
A capacitor of \(4~\mu\text{F}\) is connected as shown in the circuit. The internal resistance of the battery is \(0.5Q\). The amount of charge on the capacitor plates will be:
1. \(0\)
2. \(4~\mu\text{C}\)
3. \(16~\mu\text{C}\)
4. \(8~\mu\text{C}\)
| 1. | both \(q\) and \(V\) | 2. | the geometry of the capacitor |
| 3. | \(q\) only | 4. | \(V\) only |
| 1. | \(2C\) | 2. | \(\dfrac{C}{2}\) |
| 3. | \(4C\) | 4. | \(\dfrac{C}{4}\) |
1. \(10~\mu \text{F}\)
2. \(20~\mu \text{F}\)
3. \(30~\mu \text{F}\)
4. \(40~\mu \text{F}\)
| 1. |  |
2. |  |
| 3. |  |
4. |  |
In a parallel plate capacitor with air between the plates, each plate has an area of \(6\times10^{-3}~\text{m}^2,\) and the distance between the plates is \(3~\text{mm}.\) The capacitance of the capacitor is:
1. \(16.12~\text{pF}\)
2. \(17.71~\text{pF}\)
3. \(15.01~\text{pF}\)
4. \(11.32~\text{pF}\)
| A: | Key \(K\) is kept closed and plates of capacitors are moved apart using insulating handle. |
| B: | Key \(K\) is opened and plates of capacitors are moved apart using the insulating handle. |
Then:
| (a) | In A: \(Q\) remains same but \(C\) changes. |
| (b) | In B: \(V\) remains same but \(C\) changes. |
| (c) | In A: \(V\) remains same and hence \(Q\) changes. |
| (d) | In B: \(Q\) remains same and hence \(V\) changes. |
1. (a), (b) only
2. (b), (c) only
3. (a), (c), (d) only
4. (c), (d) only
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