Q. No.A thin semi-circular ring of radius \(r\) has a positive charge \(q\) distributed uniformly over it. The net potential at the centre \(O\) is:
| 1. | \(-\dfrac{q}{2 \pi^{} \varepsilon_{0} r^{}} \) | 2. | \(-\dfrac{q}{4 \pi^{} \varepsilon_{0} r^{}} \) |
| 3. | \(\dfrac{q}{4 \pi^{} \varepsilon_{0} r^{}} \) | 4. | \(0\) |
Subtopic: Electric Potential |
55%
From NCERT
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A neutral spherical copper particle has a radius of \(10\) nm (\(1\) nm = \(10^{-9}\) m). It gets charged by applying the voltage slowly adding one electron at a time. Then the graph of the total charge on the particle vs the applied voltage would look like:
| 1. |  |
2. |  |
| 3. |  |
4. |  |
Subtopic: Electric Potential |
From NCERT
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If a conducting sphere of radius \(R\) is charged. Then the electric field at a distance \(r(r>R)\) from the centre of the sphere would be, (\(V=\) potential on the surface of the sphere):
| 1. | \(\dfrac{rV}{R^2}\) | 2. | \(\dfrac{R^2V}{r^3}\) |
| 3. | \(\dfrac{RV}{r^2}\) | 4. | \(\dfrac{V}{r}\) |
Subtopic: Electric Potential |
From NCERT
NEET - 2023
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Four identical point charges (\(q\) each) are placed at the four corners of a square of diagonal \(d.\) The potential at a point which is at a distance \(\dfrac{d}{2}\) above the centre of the square is:
\(\Big(k=\dfrac{1}{4\pi\varepsilon_0}\Big)\)
\(\Big(k=\dfrac{1}{4\pi\varepsilon_0}\Big)\)
| 1. | \(\dfrac{8~kq}{d}\) | 2. | \(\dfrac{4~kq}{d}\) |
| 3. | \(\dfrac{4\sqrt2~kq}{d}\) | 4. | \(\dfrac{\sqrt2~kq}{d}\) |
Subtopic: Electric Potential |
69%
From NCERT
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Two charged conducting spheres of radii \(a\) and \(b\) are connected to each other by a wire. The ratio of electric fields at the surfaces of the two spheres is:
| 1. | \(\dfrac{a}{b}\) | 2. | \(1\) |
| 3. | \(\dfrac{2a}{b}\) | 4. | \(\dfrac{b}{a}\) |
Subtopic: Electric Potential |
67%
From NCERT
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Two hollow conducting spheres of radii \(R_1\) and \(R_2\) \(\left ( R_1\gg R_2 \right )\) are concentric and have equal charges. The potential would be:
| 1. | dependent on the material property of the sphere |
| 2. | more on the bigger sphere |
| 3. | more on the smaller sphere |
| 4. | equal on both the spheres |
Subtopic: Electric Potential |
71%
From NCERT
PMT - 2022
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Twenty seven drops of same size are charged at \(220~\text{V}\) each. They combine to form a bigger drop. Calculate the potential of the bigger drop:
| 1. | \(1520~\text{V}\) | 2. | \(1980~\text{V}\) |
| 3. | \(660~\text{V}\) | 4. | \(1320~\text{V}\) |
Subtopic: Electric Potential |
70%
From NCERT
NEET - 2021
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Two tiny spheres carrying charges of \(1.5\) µC and \(2.5\) µC are located \(30\) cm apart. What is the potential at a point \(10\) cm from the midpoint in a plane normal to the line and passing through the mid-point?
| 1. | \(1.5\times 10^{5}\) V | 2. | \(1.0\times 10^{5}\) V |
| 3. | \(2.4\times 10^{5}\) V | 4. | \(2.0\times 10^{5}\) V |
Subtopic: Electric Potential |
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The value of the electric potential at a distance of \(9~\text{cm}\) from the point charge \(4\times10^{-7}~\text{C}\) is:
\(\left[\mathrm{Given}\dfrac{1}{4\pi\varepsilon_{0}}=9\times10^{9}~\text{N m}^{2}~\text{C}^{-2}\right]\)
\(\left[\mathrm{Given}\dfrac{1}{4\pi\varepsilon_{0}}=9\times10^{9}~\text{N m}^{2}~\text{C}^{-2}\right]\)
| 1. | \(4\times10^2~\text V\) | 2. | \(44.4~\text V\) |
| 3. | \(4.4\times10^5~\text V\) | 4. | \(4\times10^4~\text V\) |
Subtopic: Electric Potential |
78%
From NCERT
NEET - 2024
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Electric potential is minimum at a point:
| 1. | on equatorial position |
| 2. | on axial position with \(\theta=0^{\circ}\) |
| 3. | on axial position with \(\theta=180^{\circ}\) |
| 4. | on thw line making an angle \(45^\circ\)with the dipole axis |
Subtopic: Electric Potential |
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