An ideal gas is made to undergo a cycle depicted by the \((P\text-V)\) diagram alongside. If the curved line from \(A\) to \(B\) is adiabatic, then:
1. | the efficiency of this cycle is given by unity as no heat is released during the cycle. |
2. | heat is absorbed in the upper part of the straight-line path and released in the lower. |
3. | if \(T_1\) and \(T_2\) are the maximum and minimum temperatures reached during the cycle, then the efficiency is given by, \(\left(1-\dfrac{T_2}{T_1}\right).\) |
4. | the cycle can only be carried out in the reverse direction as shown in the figure. |
In this \((P\text -V)\) diagram below the dashed curved line is adiabatic.
For a process, that is described by a straight line joining two points \(X\) and \(Y\) on the adiabat (solid line In the diagram) heat is:
(consider the variations in temperature from \(X\) to \(Y\) along the straight line.)
1. | \(X\) to \(Y.\) | absorbed throughout from
2. | \(X\) to \(Y.\) | released throughout from
3. | \(X\) up to an intermediate point \(Z\) (not shown In the figure) and then released from \(Z\) to \(Y.\) | absorbed from
4. | \(X\) up to an Intermediate point \(Z\) (not shown in the figure) and then absorbed from \(Z\) to \(Y.\) | released from
1. | \(W_1<W_2<W_3\) | 2. | \(W_2<W_1=W_3\) |
3. | \(W_2<W_1<W_3\) | 4. | \(W_1>W_2>W_3\) |