The diazonium salt of which of the following compounds will form a coloured dye on
reaction with β-Naphthol in NaOH?
 

1.
2.
3.
4.

Among the following, the reaction/s that will not give p-aminoazobenzene is/are:

A.
B.
C.

1. A only

2. B only

3. C only

4. A and B

An amine, on reaction with benzene sulphonyl chloride, produces a compound that is insoluble in an alkaline solution. This amine can be prepared by ammonolysis of ethyl chloride. What is the correct structure of this amine?

1.
2.	${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2$
3.	${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{NHCH}}_3$
4.	${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{NH}-{\mathrm{CH}}_2{\mathrm{CH}}_3$

A. Phenyl methanamine
B. N, N-Dimethylaniline
C. N-Methyl aniline
D. Benzenamine

Choose the correct order of basic nature of the above amines.

1. A > C > B > D

2. D > C > B > A

3. D > B > C > A

4. A > B > C > D

Match Column-I with Column-II 

Column-I		Column-II
(a)		(i)	Wurtz reaction
(b)		(ii)	Sandmeyer reaction
(c)	\(\small2 \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Cl}+2 \mathrm{Na} \xrightarrow{\text { Ether }}\\~~~~~~~~ \mathrm{C}_2 \mathrm{H}_5-\mathrm{C}_2 \mathrm{H}_5+2 \mathrm{NaCl}\)	(iii)	Fitting reaction
(d)	\(\small2 \mathrm{C}_6 \mathrm{H}_5 \mathrm{Cl}+2 \mathrm{Na} \xrightarrow{\text { Ether }}\\~~~~~~~~~ \mathrm{C}_6 \mathrm{H}_5-\mathrm{C}_6 \mathrm{H}_5+2 \mathrm{NaCl}\)	(iv)	Gatterman reaction

Choose the correct answer from the options given below :

The compounds 'A' and 'B' respectively are: 

1. Nitrobenzene and Chlorobenzene

2. Nitrobenzene and Fluorobenzene

3. Phenol and Benzene

4. Benzene diazonium chloride and Fluorobenzene

Match List I with List II and select the correct answer using the codes given below the Lists:

List I		List II
(a)		(i)	Br2/NaOH
(b)		(ii)	H2/Pd-BaSO4
(c)		(iii)	Zn(Hg)/Conc.HCl
(d)		(iv)	Cl2 /Red P, H2O

Choose the correct answer from the options given below :

1. (a)–(ii), (b)–(i), (c)–(iv), (d)–(iii)

2. (a)–(iii), (b)–(iv), (c)–(i), (d)–(ii)

3. (a)–(ii), (b)–(iv), (c)–(i), (d)–(iii)

4. (a)–(iii), (b)–(i), (c)–(iv), (d)–(ii)

What is the correct sequence of reagents used for converting nitrobenzene into m-dibromobenzene ?

1. $\begin{array}{l}\stackrel{{\mathrm{NaNO}}_2}{\to }/\stackrel{\mathrm{HCl}}{\to }/\stackrel{\mathrm{KBr}}{\to }/\stackrel{{\mathrm{H}}^{+}}{\to }\end{array}$

2. $\begin{array}{l}\stackrel{{\mathrm{Br}}_2/\mathrm{Fe}}{\to }/\stackrel{\mathrm{Sn}/\mathrm{HCl}}{\to }/\stackrel{{\mathrm{NaNO}}_2/\mathrm{HCl}}{\to }/\stackrel{\mathrm{CuBr}/\mathrm{HBr}}{\to }\end{array}$

3. $\begin{array}{l}\stackrel{\mathrm{Sn}/\mathrm{HCl}}{\to }/\stackrel{\mathrm{KBr}}{\to }/\stackrel{{\mathrm{Br}}_2}{\to }/\stackrel{{\mathrm{H}}^{+}}{\to }\\ \end{array}$

4.  $\stackrel{\mathrm{Sn}/\mathrm{HCl}}{\to }/\stackrel{{\mathrm{Br}}_2}{\to }/\stackrel{{\mathrm{NaNO}}_2}{\to }/\stackrel{\mathrm{NaBr}}{\to }$

In the following reaction, the reason why meta-nitro product also formed is:

1. Low temperature

2. –NH₂ group is highly meta-directive

3. Formation of anilinium ion

4. –NO₂ substitution always takes place at meta-position

The correct statement about the given chemical reaction is :

1. -NH₂ group is ortho and para directive, so product (B) is not possible.

2. Reaction is possible and compound (B) will be the major product.

3. The reaction will form sulphonated product instead of nitration.

4. Reaction is possible and compound (A) will be major product.