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Q. No.To an AC power supply of \(220~\text V\) at \(50~\text{Hz},\) a resistor of \(20~\Omega,\) a capacitor of reactance \(25~\Omega\) and an inductor of reactance \(45~\Omega\) are connected in series. The corresponding current in the circuit and the phase angle between the current and the voltage is, respectively:
1. \(15.6~\text {A and} ~30^\circ\)
2. \(15.6~\text {A and} ~45^\circ\)
3. \(7.8~\text {A and} ~30^\circ\)
4. \(7.8~\text {A and} ~45^\circ\)
1. \(15.6~\text {A and} ~30^\circ\)
2. \(15.6~\text {A and} ~45^\circ\)
3. \(7.8~\text {A and} ~30^\circ\)
4. \(7.8~\text {A and} ~45^\circ\)
Subtopic: Different Types of AC Circuits |
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Please attempt this question first.
In an ideal transformer, the turns ratio is \(\frac{N_p}{N_s}=\frac{1}{2} .\) The ratio \(V_s:V_p\) is equal to (the symbols carry their usual meaning):
1. \(2:1\)
2. \(1:1\)
3. \(1:4\)
4. \(1:2\)
1. \(2:1\)
2. \(1:1\)
3. \(1:4\)
4. \(1:2\)
Subtopic: Transformer |
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A \(10~\mu\text F\) capacitor is connected to a \(210~\text V,50~\text{Hz}\) source as shown in the figure. The peak current in the circuit is nearly \((\pi = 3.14)\):
1. \(0.93~\text A\)
2. \(1.20~\text A\)
3. \(0.35~\text A\)
4. \(0.58~\text A\)
1. \(0.93~\text A\)
2. \(1.20~\text A\)
3. \(0.35~\text A\)
4. \(0.58~\text A\)
Subtopic: RMS & Average Values |
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\(L,C\) and \(R\) represent the value of inductance, capacitance, and resistance, respectively. The factor which has the same dimensions as that of the inverse of the resonance frequency is:
| 1. | \(\sqrt{LC}\) | 2. | \(\sqrt{\dfrac{L}{C}}\) |
| 3. | \(\dfrac{C}{L}\) | 4. | \(\dfrac{R}{L}\) |
Subtopic: Different Types of AC Circuits |
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In the circuit shown below, the inductance \(L\) is connected to a source. The current flowing in the circuit is \({I=I_{0}\sin\omega t.}\) The voltage drop \((V_L)\) across \(L\) is:
| 1. | \(\omega L~I_0\sin\omega t\) | 2. | \(\frac{{I}_0}{\omega{L}}\sin\omega t\) |
| 3. | \(\frac{{I}_0}{\omega{L}}\cos\omega t\) | 4. | \(\omega L~I_0\cos\omega t\) |
Subtopic: Different Types of AC Circuits |
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A step-up transformer is connected to an AC mains supply of \(220~\text V\) to operate at \(11000~\text V, 88~\text W.\) The current in the secondary circuit, ignoring the power loss in the transformer, is:
1. \(8~\text{mA}\)
2. \(4~\text{mA}\)
3. \(0.4~\text{A}\)
4. \(4~\text{A}\)
1. \(8~\text{mA}\)
2. \(4~\text{mA}\)
3. \(0.4~\text{A}\)
4. \(4~\text{A}\)
Subtopic: Transformer |
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An AC source is connected to a capacitor \(C\). Due to decrease in its operating frequency:
| 1. | capacitive reactance remains constant |
| 2. | capacitive reactance decreases. |
| 3. | displacement current increases. |
| 4. | displacement current decreases. |
Subtopic: Different Types of AC Circuits |
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A \(12~\text{V},60~\text{W}\) lamp is connected to the secondary of a step-down transformer, whose primary is connected to AC mains of \(220~\text{V}\). Assuming the transformer to be ideal, what is the current in the primary winding?
1. \(0.37~\text{A}\)
2. \(0.27~\text{A}\)
3. \(2.7~\text{A}\)
4. \(3.7~\text{A}\)
1. \(0.37~\text{A}\)
2. \(0.27~\text{A}\)
3. \(2.7~\text{A}\)
4. \(3.7~\text{A}\)
Subtopic: Transformer |
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In a series \({LCR}\) circuit, the inductance \({L}\) is \(10~\text{mH}\), capacitance \({C}\) is \(1~\mu\text{F}\) and resistance \({R}\) is \(100~\Omega\). The frequency at which resonance occurs is:
1. \(1.59~\text{kHz}\)
2. \(15.9~\text{rad/s}\)
3. \(15.9~\text{kHz}\)
4. \(1.59~\text{rad/s}\)
1. \(1.59~\text{kHz}\)
2. \(15.9~\text{rad/s}\)
3. \(15.9~\text{kHz}\)
4. \(1.59~\text{rad/s}\)
Subtopic: Different Types of AC Circuits |
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The net impedance of the circuit (as shown in the figure) will be:
| 1. | \(25~\Omega\) | 2. | \(10\sqrt{2}~\Omega\) |
| 3. | \(15~\Omega\) | 4. | \(5\sqrt{5}~\Omega\) |
Subtopic: Different Types of AC Circuits |
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