Which is the correct order of increasing energy of the listed orbitals in the atom of titanium?
1. 3s 4s 3p 3d
2. 4s 3s 3p 3d
3. 3s 3p 3d 4s
4. 3s 3p 4s 3d

Subtopic:  AUFBAU Principle |
77%
From NCERT
NEET - 2015
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The number of d -electrons in Fe2+atomic number  Z = 26  is different from the number of:

1. s-electrons in Mg (Z = 12)
2. p-electrons in Cl (Z = 17)
3. d-electrons in Fe (Z = 26)
4. p-electrons in Ne (Z = 10)

Subtopic:  AUFBAU Principle |
64%
From NCERT
NEET - 2015
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The angular momentum of electrons in d orbital is equal to:
1. $\sqrt{6}$ $\overline{)h}$
2. $\sqrt{2}$$\overline{)h}$
3. $2\sqrt{3}$ $\overline{)h}$
4. 0 $\overline{)h}$

Subtopic:  Quantum Numbers & Schrodinger Wave Equation |
77%
NEET - 2015
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What is the maximum number of orbitals that can be identified with the following quantum numbers?
n = 3, l = 1, m = 0

 1 1 2 2 3 3 4 4
Subtopic:  Quantum Numbers & Schrodinger Wave Equation |
59%
From NCERT
AIPMT - 2014
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Calculate the energy in corresponding to light of wavelength 45 nm:
(Planck's constant h = 6.63 × 10–34 Js: speed of light c = 3 × 108 ms–1)
1. 6.67 x 1015 J
2. 6.67 x 1011 J
3. 4.42 x 10-15 J
4. 4.42 x 10-18 J

Subtopic:  Planck's Theory |
78%
From NCERT
AIPMT - 2014
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The value of Planck's constant is 6.63 × 10–34 Js. The speed of light is 3 × 1017 nm s–1. Which value is closest to the wavelength in nanometers of a quantum of light with a frequency of 6 × 1015 s–1?

1. 25
2. 50
3. 75
4. 10
86%
From NCERT
AIPMT - 2013
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What is the maximum number of electrons that can be associated with the following set of quantum numbers?
n = 3, l = 1 and m = –1.
1. 6
2. 4
3. 2
4. 10

Subtopic:  Quantum Numbers & Schrodinger Wave Equation |
77%
From NCERT
AIPMT - 2013
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Based on equation E = –2.178 × 10–18J, $\frac{{\mathrm{Z}}^{2}}{{\mathrm{n}}^{2}}$ certain conclusions are written. Which of them is not correct?

 1 Larger the value of n, the larger the orbit radius. 2 Equation can be used to calculate the change in energy when the electron changes orbit. 3 For n = 1, the electron has a more negative energy than it does for n = 6 which means that the electron is more loosely bound in the smallest allowed orbit. 4 The negative sign in the equation simply means that the energy of the electron bound to the nucleus is lower than what it would be if the electrons were at an infinite distance from the nucleus.
Subtopic:  Bohr's Theory |
66%
From NCERT
AIPMT - 2013
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According to the law of photochemical equivalence, the energy absorbed (in ergs/mole) is given as:
(h = 6.62 × 10–27 ergs, c = 3 × 1010 cm s–1, NA = 6.02 × 1023 mol–1)

1. $${{1.196\times 10^{8}}\over{\lambda}}$$
2. $${{2.859\times 10^{5}}\over{\lambda}}$$
3. $${{2.859\times 10^{16}}\over{\lambda}}$$
4. $${{1.196\times 10^{16}}\over{\lambda}}$$
63%
From NCERT
NEET - 2013
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Maximum number of electrons in a subshell with l = 3 and n = 4 is:

1. 14

2. 16

3. 10

4. 12

Subtopic:  Quantum Numbers & Schrodinger Wave Equation |
84%
From NCERT
AIPMT - 2012
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