List I | List II | ||
a. | Micro | i. | m |
b. | Mega | ii. | m |
c. | Giga | iii. | m |
d. | Femto | iv. | m |
a | b | c | d | |
1. | i | iv | iii | ii |
2. | iii | iv | ii | i |
3. | ii | iii | iv | i |
4. | i | iii | iv | ii |
When 50.0 kg of nitrogen gas (N2) and 10.0 kg of hydrogen gas (H2) are combined, what is the quantity of ammonia gas (NH3) produced?
1. 33.0 ×103 mol
2. 56.1×103 g
3. 6.5 ×103 g
4. None of the above
A solution is prepared by adding 2 g of substance A to 18 g of water. The mass percent of the solute is:
1. 20%
2. 10%
3. 15%
4. 18%
The NaNO3 weighed out to make 50 mL of an aqueous solution containing 70.0 mg Na+ per ml is:
(Rounded off to the nearest integer) [Given: Atomic weight in g mol–1 – Na: 23; N: 14; O: 16]
1. 13 g
2. 26 g
3. 18 g
4. 22 g
Sulphuric acid reacts with sodium hydroxide as follows
When 1L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained are respectively-
1. 0.1 M, 7.10 g
2. 7.10 g, 0.025 M
3. 0.025 M, 3.55 g
4. 3.55 g, 0.25 M
One mole of oxygen gas at STP is equal to:
(a) | 6 .022× 1023 molecules of oxygen |
(b) | 6.022 × 1023 atoms of oxygen |
(c) | 16 g of oxygen molecule |
(d) | 32 g of oxygen |
Choose the correct answer from the option given below:
1. | (a) and (b) | 2. | (a) and (c) |
3. | (a) and (d) | 4. | (c) and (d) |
The mass of CaCO3 required to react completely with 25 mL of 0.75 M HCl according to the given reaction would be:
CaCO3(s) + HCl(aq) ➡ CaCl2(aq) + CO2(g) + H2O(l)
1. 0.36 g
2. 0.09 g
3. 0.96 g
4. 0.66 g
An aqueous solution of urea containing 18 g of urea in 1500 cm3 of the solution has a density of 1.052 g/cm3. If the molecular weight of urea is 60, then the molality of the solution is-
1. 0.2
2. 0.192
3. 0.064
4. 1.2
The number of significant figures in the following numbers is:
(I). | 161 cm |
(II). | 0.0161 |
(III). | 1.61 |
1. 3, 3, 3
2. 3, 4, 3
3. 3, 2, 3
4. 3, 4, 4
Percentage of C, H & N of a compound is given as follows:
C=40%, H=13.33%, N=46.67%
The empirical formula of the compound will be:
1.
2.
3.
4.