The amount of glucose required to prepare 250 mL of $$\dfrac{M}{20}$$ aqueous solution is:
(Molar mass of glucose: 180 g $$\mathrm{mol ^{-1}}$$)
1. 2.25 g
2. 4.5 g
3. 0.44 g
4. 1.125 g
Subtopic:  Concentration Based Problem |
80%
From NCERT
NEET - 2024
Hints

Mass of glucose $$\left(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\right)$$ required to be dissolved to prepare one litre of its solution which is isotone with $$15~g~L^{-1}$$solution of urea $$\mathrm{(NH_2 CONH_2)}$$ is:

(Given : Molar mass in g $$\mathrm{mol}^{-1}$$ C:12, H:1, O: 16, N:14 )

1. 55 g
2. 15 g
3. 30 g
4. 45 g
Subtopic:  Concentration Based Problem |
66%
From NCERT
NEET - 2024
Hints

The density of 1 M solution of a compound 'X' is 1.25 g mL–1. The correct option for the molality of  solution is:
(Molar mass of compound X = 85 g):
 1 0.705 m 2 1.208 m 3 1.165 m 4 0.858 m
Subtopic:  Concentration Based Problem |
65%
From NCERT
NEET - 2023
Hints

The density of a 2 M aqueous solution of NaOH is 1.28 g/$c{m}^{3}$. The molality of the solution is:
[molecular mass of NaOH = 40 $gmo{l}^{-1}$]

 1 1.20 m 2 1.56 m 3 1.67 m 4 1.32 m
Subtopic:  Concentration Based Problem |
70%
From NCERT
NEET - 2019
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Which of the following is dependent on temperature?

 1 Molarity 2 Mole fraction 3 Weight percentage 4 Molality
Subtopic:  Concentration Based Problem |
81%
From NCERT
NEET - 2017
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Calculate  the mole fraction of the solute in a 1.00 m aqueous solution.

 1 0.177 2 0.771 3 0.0534 4 0.0177
Subtopic:  Concentration Based Problem |
68%
From NCERT
NEET - 2015
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The weight of 70 % HNOconcentrated nitric acid solution that should be used to prepare 250 mL of 2.0 M HNO3  is:
1. 90.0 g conc. HNO3
2. 70.0 g conc. HNO3
3. 54.0 g conc. HNO3
4. 45.0 g conc. HNO3
Subtopic:  Concentration Based Problem |
65%
From NCERT
AIPMT - 2013
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6.02 × 1020 molecules of urea are present in 100 mL of its solution. The concentration of the solution is:
1. 0.01 M
2. 0.001 M
3. 0.1 M
4. 0.02 M
Subtopic:  Concentration Based Problem |
78%
From NCERT
AIPMT - 2013
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Mole fraction of solute in a 1.00 molal aqueous solution is:
1.  0.0177
2.  0.0344
3.  1.770
4.  0.1770

Subtopic:  Concentration Based Problem |
82%
From NCERT
AIPMT - 2011
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25.3 g of sodium carbonate, Na2CO3, is dissolved in enough water to make 250 mL of a solution. If sodium carbonate completely dissociates, the molar concentrations of sodium ion, Na+ and carbonate ion, $C{O}_{3}^{2-}$are respectively:
(molar mass of Na2CO3 = 106g mol-1)

1. 0.955 M and 1.910 M
2. 1.910 M and 0.955 M
3. 1.90 M and 1.910 M
4. 0.477 M and 0.477 M

Subtopic:  Concentration Based Problem |
71%
From NCERT
AIPMT - 2010
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