Q. No.The amount of glucose required to prepare 250 mL of \(\dfrac{M}{20}\) aqueous solution is:
(Molar mass of glucose: 180 g \(\mathrm{mol ^{-1}}\))
1. 2.25 g
2. 4.5 g
3. 0.44 g
4. 1.125 g
(Molar mass of glucose: 180 g \(\mathrm{mol ^{-1}}\))
1. 2.25 g
2. 4.5 g
3. 0.44 g
4. 1.125 g
Subtopic: Concentration Based Problem |
80%
From NCERT
NEET - 2024
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Mass of glucose \(\left(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\right)\) required to be dissolved to prepare one litre of its solution which is isotone with \(15~g~L^{-1}\)solution of urea \(\mathrm{(NH_2 CONH_2)}\) is:
(Given : Molar mass in g \(\mathrm{mol}^{-1}\) C:12, H:1, O: 16, N:14 )
1. 55 g
2. 15 g
3. 30 g
4. 45 g
(Given : Molar mass in g \(\mathrm{mol}^{-1}\) C:12, H:1, O: 16, N:14 )
1. 55 g
2. 15 g
3. 30 g
4. 45 g
Subtopic: Concentration Based Problem |
66%
From NCERT
NEET - 2024
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The density of 1 M solution of a compound 'X' is 1.25 g mL–1. The correct option for the molality of solution is:
(Molar mass of compound X = 85 g):
(Molar mass of compound X = 85 g):
| 1. | 0.705 m | 2. | 1.208 m |
| 3. | 1.165 m | 4. | 0.858 m |
Subtopic: Concentration Based Problem |
65%
From NCERT
NEET - 2023
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The density of a 2 M aqueous solution of NaOH is 1.28 g/. The molality of the solution is:
[molecular mass of NaOH = 40 ]
| 1. | 1.20 m | 2. | 1.56 m |
| 3. | 1.67 m | 4. | 1.32 m |
Subtopic: Concentration Based Problem |
70%
From NCERT
NEET - 2019
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Which of the following is dependent on temperature?
| 1. | Molarity | 2. | Mole fraction |
| 3. | Weight percentage | 4. | Molality |
Subtopic: Concentration Based Problem |
81%
From NCERT
NEET - 2017
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Calculate the mole fraction of the solute in a 1.00 m aqueous solution.
| 1. | 0.177 | 2. | 0.771 |
| 3. | 0.0534 | 4. | 0.0177 |
Subtopic: Concentration Based Problem |
68%
From NCERT
NEET - 2015
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The weight of 70 % HNO3 concentrated nitric acid solution that should be used to prepare 250 mL of 2.0 M HNO3 is:
1. 90.0 g conc. HNO3
2. 70.0 g conc. HNO3
3. 54.0 g conc. HNO3
4. 45.0 g conc. HNO3
2. 70.0 g conc. HNO3
3. 54.0 g conc. HNO3
4. 45.0 g conc. HNO3
Subtopic: Concentration Based Problem |
65%
From NCERT
AIPMT - 2013
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6.02 × 1020 molecules of urea are present in 100 mL of its solution. The concentration of the solution is:
1. 0.01 M
2. 0.001 M
3. 0.1 M
4. 0.02 M
1. 0.01 M
2. 0.001 M
3. 0.1 M
4. 0.02 M
Subtopic: Concentration Based Problem |
78%
From NCERT
AIPMT - 2013
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Mole fraction of solute in a 1.00 molal aqueous solution is:
1. 0.0177
2. 0.0344
3. 1.770
4. 0.1770
Subtopic: Concentration Based Problem |
82%
From NCERT
AIPMT - 2011
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25.3 g of sodium carbonate, Na2CO3, is dissolved in enough water to make 250 mL of a solution. If sodium carbonate completely dissociates, the molar concentrations of sodium ion, Na+ and carbonate ion, are respectively:
(molar mass of Na2CO3 = 106g mol-1)
1. 0.955 M and 1.910 M
2. 1.910 M and 0.955 M
3. 1.90 M and 1.910 M
4. 0.477 M and 0.477 M
Subtopic: Concentration Based Problem |
71%
From NCERT
AIPMT - 2010
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