1. | 13.4 g | 2. | 9.4 g |
3. | 11.4 g | 4. | 15.8 g |
1. | 240 | 2. | 225 |
3. | 204 | 4. | 198 |
Given 645 g of a compound \(C_6H_5N_3O_6\) . The number of N atoms present in this compound is:
Report x if your answer is \(x \times 10^{21} \)
\((C=12, H=1, N=14, O=16)\left(N_{A}=6.02 \times 10^{23}\right) \)
1. 5418
2. 5671
3. 5212
4. 5781