The value of K_p for the reaction,

CO₂ (g) + C (s) $\leftrightharpoons$2CO (g)

is 3.0 at 1000 K. If initially  \(P_{CO_{2}}\)= 0.48 bar and P_CO = 0 bar and pure graphite is present.
The equilibrium partial pressures of CO and CO₂ are respectively-

1.	0.56 bar; 0.15 bar	2.	0.15 bar; 0.75 bar
3.	0.66 bar; 0.15 bar	4.	0.66 bar; 0.25 bar

The value of K_c for the reaction 2A $\leftrightharpoons$B + C is 2 × 10^–3. At a given time, the composition of the reaction mixture is [A] = [B] = [C] = 3 × 10^–4 M.
The reaction will proceed:

1. In the backward direction
2. In the forward direction
3. In both direction
4. Cannot be predicted

13.8g of N₂O₄ was placed in a 1L reaction vessel at 400K and allowed to attain equilibrium

N₂O₄ (g) $\leftrightharpoons$ 2NO₂ (g)

The total pressure at equilbrium was found to be 9.15 bar. The  value of K_c is:

1. 3.2
2. 2.6
3. 2.1
4. 3.6

 

3.00 mol of PCl₅ kept in 1L closed reaction vessel was allowed to attain equilibrium at 380K. The
composition of the mixture at equilibrium is:
(Given: K_c= 1.80)

1. [PCl₅] = 1.41 M; [PCl₃] = [Cl₂] = 1.59 M
2. [PCl₅] = 1.61 M; [PCl₃] = [Cl₂] = 1.59 M
3. [PCl₅] = 1.91 M; [PCl₃] = [Cl₂] = 1.71 M
4. [PCl₅] = 2.41 M; [PCl₃] = [Cl₂] = 1.19 M

The value of ∆G^⊖ for the phosphorylation of glucose in glycolysis is 13.8 kJ/mol.
The value of K_c at 298 K is:

1. 5.21 × 10^–3
2. 3.56 × 10^–3
3. 2.81 × 10^–3
4. 3.81 × 10^–3

Hydrolysis of sucrose gives,

Sucrose + H₂O  $\leftrightharpoons$Glucose + Fructose

The equilibrium constant K_c for the reaction is 2 ×10¹³ at 300K. The value of ∆G^⊖ at 300K is:

1. – 5.64 ×10⁴ J mol^–1
2. – 7.64 ×10⁴ J mol^–1
3. – 6.64 ×10⁴ J mol^–1
4. – 8.64 ×10⁴ J mol^–1

The correct match among the following is/are:

The correct match among the following is/are-

1. a, c
2. a, b
3. b, c
4. Only c is correct

The incorrect match among the following  is:

a. HO^– = Lewis base
b. F^– = Lewis base
c. H⁺ = Lewis acid
d. BCl₃ = Lewis base

1. Both a and b
2. Only b
3. Only d
4. Both a and d

The concentration of hydrogen ions in a sample of soft drink is 3.8 × 10^–3M. The pH of soft drink is:
(Given: log 3.8 = 0.58)