The concentration of hydrogen ion in a sample of soft drink is $3.8$ $\times {10}^{-3}$ $\mathrm{M}$. The  pH of the soft drink will be:

The pH of a sample of vinegar is 3.76. The concentration of H⁺ ions in the sample will be -

$1.$ $1.74$ $\times$ ${10}^{-4}$ $\mathrm{M}$
$2.$ $2.34$ $\times$ ${10}^{-11}\mathrm{M}$
$3.$ $2.86$ $\times$ ${10}^{-10}$ $\mathrm{M}$
$4.$ $1.74$ $\times$ ${10}^{-3}$ $\mathrm{M}$

(Atomic wt of Tl =204)

When 1mL of 13.6 M HCl is diluted with water to give 1 litre of solution, the pH of the resultant solution will be:

0.561 g of KOH is dissolved in water to give 200 mL of solution at 298 K. The pH of the solution will be

The ionic product of water at 310 K is 2.7 × 10^–14.

The pH of neutral water at this temperature will be:

The ionization constant of acetic acid is 1.74 × 10^–5. The pH of acetic acid in its 0.05 M solution will be:
1. 7.81

(a) Human muscle-fluid,  pH = 6.83 

(b) Human stomach fluid, pH = 1.2

(c) Human blood, pH = 7.38           

(d) Human saliva, pH = 6.4.