2.335 g of compound X (empirical formal CoH₁₂N₄Cl₃) upon treatment with excess AgNO₃ solution produces 1.435 g of a white precipitate. The primary and secondary valences of cobalt in compound X, respectively are:

[Given Atomic mass: Co = 59, Cl = 35.5, Ag = 108]

1.	3, 6	2.	3, 4
3.	2, 4	4.	4, 3

The complex that can exhibit linkage isomerism is:

Spin-only magnetic moments of [Fe(NH₃)₆]³⁺ and [FeF₆]^3-  in BM are, respectively :

For a tetrahedral complex [MCl₄]^2-, the spin-only magnetic moment is 3.83 B.M. The element M is:

1. Co

2. Cu

3. Mn

4. Fe

The geometry and magnetic properties of [NiCl₄]^2-, respectively, are : 

1. Tetrahedral, Paramagnetic

2. Tetrahedral, Diamagnetic

3. Square planar, Paramagnetic

4. Square planar, Diamagnetic  

The crystal field stabilization energy (CFSE) for [CoCl₆]^4– is 18000 cm^–1.
The CFSE for [CoCl₄]^2–  will be:

1. $6000$ $c{m}^{-1}$

2. $16000$ $c{m}^{-1}$

3. $18000$ $c{m}^{-1}$

4. $8000$ $c{m}^{-1}$

The IUPAC name of [\(\mathrm {C r \left(en\right)_{3}}\)]\(\mathrm{C l}_{3}\)${\mathrm{}}_{}$ is:

The electronic configuration that represents the maximum magnetic moment is:

1. $d^3$

2. $d^2$

3. $d^8$

4. $d^6$(high spin)

Among the following, the compound that has the maximum coordination number is/are:

1. [Co(NH₃)₆]³⁺
2. [Cr(C₂O₄)₃]^3-
3. [CoCl₃(H₂O)₃]
4. All of the above have the same coordination number

Two complexes, ${\mathrm{PtCl}}_4·2{\mathrm{NH}}_3$ and ${\mathrm{PtCl}}_4·2\mathrm{KCl}$, do not give a precipitate of AgCl when treated with ${\mathrm{AgNO}}_3$. They give zero and three moles of ions, respectively, in solutions for one mole of the complex.  The structural formulae of both complexes are:

1. $\left[{\mathrm{PtCl}}_2{\left({\mathrm{NH}}_3\right)}_2\right]{\mathrm{Cl}}_2$ and ${\mathrm{K}}_2\left[{\mathrm{PtCl}}_6\right]$ 

2. $\left[{\mathrm{PtCl}}_4{\left({\mathrm{NH}}_3\right)}_2\right]$ and ${\mathrm{K}}_2\left[{\mathrm{PtCl}}_2{\left({\mathrm{NH}}_3\right)}_2\right]$ 

3. $\left[{\mathrm{PtCl}}_4{\left({\mathrm{NH}}_3\right)}_2\right]$ and ${\mathrm{K}}_2\left[{\mathrm{PtCl}}_6\right]$ 

4. $\left[{\mathrm{PtCl}}_4\right]·2{\mathrm{NH}}_3$ and $\left[{\mathrm{PtCl}}_4\right]·2\mathrm{KCl}$