Number of isomers of $[Pt$ ${\left(N{H}_3\right)}_4]$ $\left[CuC{l}_4\right]$ complex are:

The IUPAC name of $\left[Co{\left(N{H}_3\right)}_{3}ClBrN{O}_2\right]$ will be:

1. Triamminebromochloronitrocobaltate (III)
2. Triamminebromochloronitrocobalt (III)
3. Triamminebromonitrochlorocobalt (III)
4. Triamminenitrobromochlorocobalt (III)

The coordination compound that will give four isomers is:

1. [Fe(en)₃]Cl₃

2. [Co(en)₂Cl₂]Cl

3. [Fe(PPh₃)₃NH₃ClBr]Cl

4. [Co(PPh₃)₃Cl]Cl₃

The coordination compound that gives the maximum number of isomers is:

1. [Co(NH₃)₄Cl₂]

2. [Ni(en)(NH₃)₄]²⁺

3. [Ni(C₂O₄)(en)₂]

4. [Cr(SCN)₂(NH₃)₄]⁺

The octahedral complex that will not show geometrical isomerism is: 
 (A and B are monodentate ligands)

Coordination compound that would exhibit optical isomerism is:

Which one of the following pair represents stereoisomerism:

1. Linkage isomerism and Geometrical isomerism

2. Chain isomerism and Rotational isomerism

3. Optical isomerism and Geometrical isomerism

4. Structural isomerism and Geometrical isomerism

Which one of the following is expected to exhibit optical isomerism?
(en = ethylenediamine)

1. cis-[Pt(NH₃)₂Cl₂]  

2. cis-[Co(en)₂Cl₂]

3. trans−[Co(en)₂Cl₂]

4. trans−[Pt(NH₃)₂Cl₂]