The shape of Fe(CO)₅ is:

1.	Octahedral	2.	Square planar
3.	Trigonal bipyramidal	4.	Square pyramidal

Which one of the following is expected to exhibit optical isomerism?
(en = ethylenediamine)

1. cis-[Pt(NH₃)₂Cl₂]  

2. cis-[Co(en)₂Cl₂]

3. trans−[Co(en)₂Cl₂]

4. trans−[Pt(NH₃)₂Cl₂]

Mg is present in:

Number of isomers of $[Pt$ ${\left(N{H}_3\right)}_4]$ $\left[CuC{l}_4\right]$ complex are:

Which one of the following is an inner orbital complex as well as is diamagnetic in behaviour?

1. [Zn (NH₃)₆]²⁺

2. [Ni (NH₃)₆]²⁺

3. [Cr (NH₃)₆]³⁺

4. [Co (NH₃)₆]³⁺

The coordination compound that will give four isomers is:

1. [Fe(en)₃]Cl₃

2. [Co(en)₂Cl₂]Cl

3. [Fe(PPh₃)₃NH₃ClBr]Cl

4. [Co(PPh₃)₃Cl]Cl₃

The IUPAC name of $\left[Co{\left(N{H}_3\right)}_{3}ClBrN{O}_2\right]$ will be:

1. Triamminebromochloronitrocobaltate (III)
2. Triamminebromochloronitrocobalt (III)
3. Triamminebromonitrochlorocobalt (III)
4. Triamminenitrobromochlorocobalt (III)

$[Cu{\left(N{H}_3\right)}_4{]}^{+2}$ reacts with $HN{O}_3$ in excess of water and gives: 

1. $Cu{\left(OH\right)}_2$

2. $Cu{\left(N{O}_3\right)}_2$

3. $Cu{\left(H_{2}O\right)}^{-2}$

4. None of the above 

In [Cr(NH₃)₆](Br)₃, number of unpaired electrons in Cr is:

Which of the following does not have a metal-carbon bond:

1. ${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{MgBr}$

2. $\mathrm{K}\left[\mathrm{Pt}\left({\mathrm{C}}_2{\mathrm{H}}_4\right){\mathrm{Cl}}_3\right]$

3. $\mathrm{Ni}(\mathrm{CO}{)}_4$

4. $\mathrm{Al}{\left({\mathrm{OC}}_2{\mathrm{H}}_5\right)}_3$