Maximum oxidation state is shown by:
1. La
2. Gd
3. Eu
4. Am
An incorrect statement among the following is :
1. | La(OH)3 is less basic than Lu(OH)3 |
2. | In Lanthanide series, ionic radius of Ln+3 ions decreases. |
3. | La is an element of a transition and not of Lanthanide series. |
4. | The atomic radius of Zr and Hf are the same because of Lanthanide contraction. |
The general electronic configuration of lanthanoids is:
1. (n – 2) f 1–14 (n – 1) s2 p6 d0–1 ns2
2. (n – 2) f 10–14 (n – 1) d0–1 ns2
3. (n – 2) f 0–14 (n – 1) d10 ns2
4. (n – 2) d0–1 (n – 1) f 1–14 ns2
The correct order of ionic radii of Y3+, La3+, Eu3+, and Lu3+ is:
(Atomic nos. Y = 39, La = 57, Eu = 63, Lu = 71)
1. Y3+ < La3+ < Eu3+ < Lu3+
2. Y3+ < Lu3+ < Eu3+ < La3+
3. Lu3+ < Eu3+ < La3+ < Y3+
4. La3+ < Eu3+ < Lu3+ < Y3+
The main reason for a larger number of oxidation states exhibited by the actinoids than the corresponding lanthanoids is:
1. | Larger atomic size of actinoids than the lanthanoids |
2. | More energy difference between 5f and 6d orbitals than between 4f and 5d orbitals |
3. | Lesser energy difference between 5f and 6d orbitals than between 4f and 5d orbitals |
4. | Greater reactive nature of the actinoids than the lanthanoids |