Q. No.Given below are two statements:
In the light of the above statements, choose the correct answer from the option given below :
1. Both Statement I and Statement II are false.
2. Statement I is correct but Statement II is false.
3. Statement I is incorrect but Statement II is true.
4. Both Statement I and Statement II are true.
| Statement I: | Aniline does not undergo Friedel-Crafts alkylation reaction. |
| Statement II: | Aniline cannot be prepared through Gabriel synthesis. |
1. Both Statement I and Statement II are false.
2. Statement I is correct but Statement II is false.
3. Statement I is incorrect but Statement II is true.
4. Both Statement I and Statement II are true.
Subtopic: Amines - Preparation & Properties | Identification of Primary, Secondary & Tertiary Amines |
64%
From NCERT
NEET - 2024
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Identify the major product C formed in the following reaction sequence:
1. Butylamine
2. Butanamide
3. \(\alpha-\) Bromobutanoic acid
4. Propylamine
1. Butylamine
2. Butanamide
3. \(\alpha-\) Bromobutanoic acid
4. Propylamine
Subtopic: Amines - Preparation & Properties |
58%
From NCERT
NEET - 2024
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Among the given reactions, which one does not result in the formation of a primary amine as the product?
| 1. |  |
| 2. |  |
| 3. |  |
| 4. |  |
Subtopic: Amines - Preparation & Properties |
71%
From NCERT
NEET - 2023
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Subtopic: Amines - Preparation & Properties |
From NCERT
NEET - 2023
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Match list-I with list-II:
| List-I (Amines) | List-II (pKb values) | ||
| (a) | N-Methylmethanamine | (i) | 9.30 |
| (b) | Ammonia | (ii) | 9.38 |
| (c) | N-Methylaniline | (iii) | 4.75 |
| (d) | Benzenamine | (iv) | 3.27 |
| (a) | (b) | (c) | (d) | |
| 1. | (iv) | (ii) | (i) | (iii) |
| 2. | (iv) | (iii) | (i) | (ii) |
| 3. | (iii) | (iv) | (i) | (ii) |
| 4. | (i) | (iv) | (iii) | (ii) |
Subtopic: Amines - Preparation & Properties |
67%
From NCERT
NEET - 2022
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Subtopic: Amines - Preparation & Properties |
67%
From NCERT
NEET - 2022
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Match column I (Reaction) with column II (Product formed) and mark the appropriate choice:
| Column - I (Reaction) |
Column - II (Product formed) |
||
| (a) | Gabriel synthesis | (i) | Benzaldehyde |
| (b) | Kolbe synthesis | (ii) | Ethers |
| (c) | Williamson synthesis | (iii) | Primary amines |
| (d) | Etard reaction | (iv) | Salicylic acid |
| (a) | (b) | (c) | (d) | |
| 1. | (iii) | (i) | (ii) | (iv) |
| 2. | (ii) | (iii) | (i) | (iv) |
| 3. | (iv) | (iii) | (i) | (ii) |
| 4. | (iii) | (iv) | (ii) | (i) |
Subtopic: Amines - Preparation & Properties |
80%
From NCERT
NEET - 2022
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The reaction of propanamide with ethanolic sodium hydroxide and bromine will give:
| 1. | Ethylamine | 2. | Methylamine |
| 3. | Propylamine | 4. | Aniline |
Subtopic: Amines - Preparation & Properties |
72%
From NCERT
NEET - 2020
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What is the correct order of the methyl-substituted amines' basic strength in an aqueous solution?
1. CH3NH2 > (CH3)2NH > (CH3)3N
2. (CH3)2NH > CH3NH2 > (CH3)3N
3. (CH3)3N > CH3NH2 > (CH3)2NH
4. (CH3)3N > CH3NH2 > (CH3)2NH
1. CH3NH2 > (CH3)2NH > (CH3)3N
2. (CH3)2NH > CH3NH2 > (CH3)3N
3. (CH3)3N > CH3NH2 > (CH3)2NH
4. (CH3)3N > CH3NH2 > (CH3)2NH
Subtopic: Amines - Preparation & Properties |
75%
From NCERT
NEET - 2019
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The nitration of aniline in a strong acidic medium results in the formation of m-nitroaniline because:
| 1. | In spite of substituents nitro group always goes to only m-position |
| 2. | In electrophilic substitution reactions amino group is meta directive |
| 3. | In absence of substituents nitro group always goes to only m-position |
| 4. | In an acidic (strong) medium aniline is present as anilinium ion |
Subtopic: Amines - Preparation & Properties |
71%
From NCERT
NEET - 2018
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